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vladimir2022 [97]
3 years ago
9

If an object has a volume of 45 cm^3 what is the volume in ml?

Chemistry
1 answer:
AlexFokin [52]3 years ago
3 0

Answer:

The answer is

<h2>45 mL</h2>

Explanation:

To convert the volume of an object from cm³ to mL we use the conversion

<h3>1 cm³ = 1 mL</h3>

From the question

If 1 cm³ = 1 mL

Then 45 cm³ = 45 mL

Hope this helps you

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A central atom has two lone pairs on opposite sides and four single bonds. What is the molecule geometry of the result?
ryzh [129]

The molecular geometry is square planar.

According to the Valence Shell Electron Pair Repulsion theory (VSEPR), the shape of a molecule is determined by the number of valence electrons surrounding the outermost shell of the central atom in the molecule.

In this case, the expected geometry based on VSEPR theory is octahedral. However, the lone pairs on opposite sides of the four single bonds leads to a square planar molecular geometry.

Learn more; brainly.com/question/24396703

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3 years ago
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Challenge question: This question is worth 6 points. As you saw in problem 9 we can have species bound to a central metal ion. T
GenaCL600 [577]

Answer:

CN^- is a strong field ligand

Explanation:

The complex, hexacyanoferrate II is an Fe^2+ specie. Fe^2+ is a d^6 specie. It may exist as high spin (paramagnetic) or low spin (diamagnetic) depending on the ligand. The energy of the d-orbitals become nondegenerate upon approach of a ligand. The extent of separation of the two orbitals and the energy between them is defined as the magnitude of crystal field splitting (∆o).

Ligands that cause a large crystal field splitting such as CN^- are called strong field ligands. They lead to the formation of diamagnetic species. Strong field ligands occur towards the end of the spectrochemical series of ligands.

Hence the complex, Fe(CN)6 4− is diamagnetic because the cyanide ion is a strong field ligand that causes the six d-electrons present to pair up in a low spin arrangement.

5 0
3 years ago
What is the molarity of solution obtained when 5.71 g of sodium carbonate-10-water is dissolved in water and made up to 250.0 cm
disa [49]

We have to know the molarity of solution obtained when 5.71 g of Na₂CO₃.10 H₂O is dissolved in water and made up to 250 cm³ solution.

The molarity of solution obtained when 5.71 g of sodium carbonate-10-water (Na₂CO₃.10 H₂O)  is dissolved in water and made up to 250.0 cm^3 solutionis: (A) 0.08 mol dm⁻³

The molarit y of solution means the number of moles of solute present in one litre of solution. Here solute is Na₂CO₃.10 H₂O and solvent is water. Volume of solution is 250 cm³.

Molar mass of Na₂CO₃.10 H₂O is 286 grams which means mass of one mole of Na₂CO₃.10 H₂O is 286 grams.

5.71 grams of Na₂CO₃.10 H₂O is equal to \frac{5.71}{286}= 0.0199 moles of Na₂CO₃.10 H₂O. So, 0.0199 moles of Na₂CO₃.10 H₂O present in 250 cm³ volume of solution.

Hence, number of moles of Na₂CO₃.10 H₂O present in one litre (equal to 1000 cm³) of solution is \frac{0.0199 X 1000}{250} = 0.0796 moles. So, the molarity of the solution is 0.0796 mol/dm³ ≅ 0.08 mol/dm³


3 0
3 years ago
A<br> is often written as an if/then statement.<br> O prediction<br> O law<br> O theory<br> O guess
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The answer is theory because it says if and that means theory
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