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prisoha [69]
3 years ago
5

What would the acceleration due to gravity on Mars be if a 40 kg mass fell to the

Physics
1 answer:
Effectus [21]3 years ago
4 0

The acceleration due to gravity on Mars is 3.75 m/s^2.

<u>Given the following data:</u>

Mass of object = 40 kg

Time = 10 seconds

Weight of object = 150 Newton.

To find the acceleration due to gravity on Mars;

In this exercise, you're required to solve for the acceleration due to gravity of an object on Mars that fell to the surface.

Mathematically, the weight of an object is calculated by using the following formula;

Weight = mg

<u>Where:</u>

m is the mass of an object.

g is the acceleration due to gravity.

Substituting the given values into the formula, we have;

150 = 40 × g

g = \frac{150}{40}

Acceleration due to gravity, g = 3.75 m/s^2

Therefore, the acceleration due to gravity on Mars is 3.75 m/s^2.

Read more: brainly.com/question/18320053

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A 235 kg crate is pulled across a horizontal surface with a force of 760 N applied at an
AnnyKZ [126]

Answer:

658.16N

Explanation:

Step one:

given data

mass m= 235kg

Force F= 760N

angle= 30 degrees

Required

The horizontal component of the force

Step two:

The horizontal component of the force

Fh= 760cos∅

Fh=760cos30

Fh=760*0.8660

Fh=658.16N

3 0
3 years ago
What is the definition of differentiation geology?
UkoKoshka [18]
Any process in which a mixture of materials separates out partially
5 0
4 years ago
Viewing moving objects from pond water under his microscope and named then animalcules
pogonyaev
I think it was either Robert Hook or Anton Van Leevwen Hoek
3 0
3 years ago
An eagle is flying horizontally at a speed of 3.10 m/s when the fish in her talons wiggles loose and falls into the lake 6.10 m
Alinara [238K]

Answer:

10.93m/s with the assumption that the water in the lake is still (the water has a speed of zero)

Explanation:

The velocity of the fish relative to the water when it hits the water surface is equal to the resultant velocity between the fish and the water when it hits it.

The fish drops on the water surface vertically with a vertical velocity v. Nothing was said about the velocity of the water, hence we can safely assume that the velocity if the water in the lake is zero, meaning that it is still. Therefore the relative velocity becomes equal to the velocity v with which the fish strikes the water surface.

We use the first equation of motion for a free-falling body to obtain v as follows;

v = u + gt....................(1)

where g is acceleration due to gravity taken as 9.8m/s/s

It should also be noted that the horizontal and vertical components of the motion are independent of each other, hence we take u = 0 as the fish falls vertically.

To obtain t, we use the second equation of motion as stated;

h=ut+gt^2/2.................(2)

Given; h = 6.10m.

since u = 0 for the vertical motion;  equation (2) can be written as follows;

h=\frac{1}{2}gt^2............(3)

substituting;

6.1=\frac{1}{2}*9.8*t^2\\6.1=4.9t^2\\hence\\t^2=6.1/4.9\\t^2=1.24\\t=\sqrt{1.24}=1.12s

Putting this value of t in equation (1) we obtain the following;

v = 0 + 9.8*1.12

v = 10.93m/s

5 0
3 years ago
A car has a kinetic energy of 41.6 kJ.
musickatia [10]
K=1/2 mv2

M=?

41.6kj convert to joules by multiplying by 1000 so it will be 41,600J because the unit of kinetic energy is in joules.

41,600=1/2(m)(8)

Arrange the equation it will be:

M= 41,600/4 = 10,400

Final answer is:
m= 10,400 kg
4 0
2 years ago
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