Answer:
2.9 N
Explanation:
When the separation distance, r, is 0.5 m, the electrostatic force is 0.32 N. Electrostatic force is given as:
F = (k * q1 * q2) / r²
Where F = force acting on the balloons
k = Coulombs constant
Therefore:
0.32 = (k * q1 * q2) / 0.5²
=> k * q1 * q2 = 0.32 * 0.5² ------------(1)
When the distance is decreased by 3, that is r = r/3 = 0.5/3
F = (k * q1 * q2) / (0.5/3)² ------------(2)
Putting (1) into (2):
=> F = (0.32 * 0.5²) / (0.5/3)²
F = (0.32 * 0.5² * 3²) / 0.5²
F = 2.9 N
Therefore, the force would be 2.9 N
Answer:
<em>Good Luck!</em>
Explanation:
Force applied by first student (F1) = 80 N
Force applied by the second student (F2) = 40 N
Displacement (d) = 10 m
Work done by first student (W1) = F1d = 80*10 = 800 J
Work done by second student (W2) = F2d = 40*10 = 400 J
Hence, the work done by the pushing student is 800 J and that by pulling student is
<h2> <u><em>400 J</em></u></h2>
Scientists could investigate this idea by making cathode ray tubes out of different materials to see if the ray was the same.
Answer:
False
Explanation:
The steel ball and the wooden ball do not have the same force acting on them because their masses are different. But, they have the same acceleration which is the acceleration due to gravity g = 9.8 m/s².
Using the equation of motion under freefall, s = ut +1/2gt². Since u = 0,
s = 1/2gt² ⇒ t = √(2s/g)
Since. s = height is the same for both objects, they land at the same time neglecting air resistance.