B. 1/7 i just took the test and thats what i got hope it helps
Answer:
51 m^2
Step-by-step explanation:
The shaded area is the difference between the area of the overall figure and that of the rectangular cutout.
The applicable formulas are ...
area of a triangle:
A = (1/2)bh
area of a rectangle:
A = bh
area of a trapezoid:
A = (1/2)(b1 +b2)h
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We note that the area of a triangle depends only on the length of its base and its height. The actual shape does not matter. Thus, we can shift the peak of the triangular portion of the shape (that portion above the top horizontal line) so that it lines up with one vertical side or the other of the figure. That makes the overall shape a trapezoid with bases 16 m and 10 m. The area of that trapezoid is then ...
A = (1/2)(16 m + 10 m)(5 m) = 65 m^2
The area of the white internal rectangle is ...
A = (2 m)(7 m) = 14 m^2
So, the shaded area is the difference:
65 m^2 -14 m^2 = 51 m^2 . . . . shaded area of the composite figure
_____
<em>Alternate approach</em>
Of course, you can also figure the area by adding the area of the triangular "roof" to the area of the larger rectangle, then subtracting the area of the smaller rectangle. Using the above formulas, that approach gives ...
(1/2)(5 m)(16 m - 10 m) + (5 m)(10 m) - (2 m)(7 m) = 15 m^2 + 50 m^2 -14 m^2
= 51 m^2
Answer:
-1/3 < x <(or equal to) 2
Step-by-step explanation:
Firstly divide your inequality into two separate inequalities...
1) -1 < 6x + 1...then solve for the first one..,which then gives you....;
-2 < 6x....which gives us our first solution (x > -1/3)
Then the second inequality
2) 6x + 1 <(or equal to) 13
which then gives you....,
6x <(or equal to) 12...which then gives our second solution...( x <(or equal to) 2)
Then combine the two solutions into a compound solution
-1/3 < x <(or equal to) 2
Multiply first equation by -5 and 2nd by 2, add them
15x+20y=-100
<u>2x-20y=32 +</u>
17x+0y=-68
17x=-68
divide both sides by 17
x=-4
the x value is -4
Total distance the rover need to travel is 
.
<u>Step-by-step explanation:</u>
We have , Garne Problem med . A rover needs to travel mile to reach its destination traveled mile. a rover needs to travel 5/8 mile to reach its destination it has already travel 3/8 miles . We need to find that how much farther does the rover need to travel , Let's do it step by step:
First , rover has already traveled 3/8 miles , Let total distance to be traveled by rover is D :
⇒ 
, where d is distance left to cover .
Now, rover need to travel 5/8 miles more to reach destination :
⇒ , where d is distance left to cover , So 
⇒
⇒ 
⇒ 
⇒ 
⇒
∴ Total distance the rover need to travel is .
