Answer:
Step-by-step explanation:
Hello!
The study variable is:
X: number of customers that recognize a new product out of 120.
There are two possible recordable outcomes for this variable, the customer can either "recognize the new product" or " don't recognize the new product". The number of trials is fixed, assuming that each customer is independent of the others and the probability of success is the same for all customers, p= 0.6, then we can say this variable has a binomial distribution.
The sample proportion obtained is:
p'= 54/120= 0.45
Considering that the sample size is large enough (n≥30) you can apply the Central Limit Theorem and approximate the distribution of the sample proportion to normal: p' ≈ N(p;
)
The other conditions for this approximation are also met: (n*p)≥5 and (n*q)≥5
The probability of getting the calculated sample proportion, or lower is:
P(X≤0.45)= P(Z≤
)= P(Z≤-3.35)= 0.000
This type of problem is for the sample proportion.
I hope this helps!
The maximum units is 200 and , Total revenue is $8,000
<u>Step-by-step explanation:</u>
Here we have , A manufacturer finds that the revenue generated by selling of cortan commodity is given by function R(x)=80x-0.2x^ 2 , where he maximum reveremany should be manufactured to obtain this maximum units .Let's find out:
We have following function as
. Let's differentiate this and equate it to zero to find value of x for which the function is maximum!
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Now , Value of function at x=200 is :
⇒ 
⇒ 
⇒ 
Therefore , The maximum units is 200 and , Total revenue is $8,000
For the first one, you did good. I will just suggest a couple things.
Statement Reason
JK ≅ LM Given
<JKM ≅ < LMK Given (You did both of these steps so well done.)
MK ≅ MK Reflexive Property (Your angle pair is congruent but isn't one of the interior angle of the triangles you are trying to prove.)
ΔJMK ≅ ΔLKM SAS
Problem 2: (You also have a lot of great stuff here.)
Statement Reason
DE ║ FG Given
DE ≅ FG Given
<DEF≅<FGH Given
<EDF≅<GFH Corresponding Angles (You don't need to know that F is the midpoint but you got corresponding angle pair which is correct.)
ΔEDF≅ΔGFH ASA
<DFE≅<FHG CPCTC
Answer:
(not this) 3/4-5+9-2/4+2
Step-by-step explanation:
1 1/3 instead of 3/4 and 2/4