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3 years ago

9

The diagram shows 28 lattice points, each one unit from its nearest neighbors. Segment AB meets segment CD at E. Find the length

of segment AE.

1 answer:

IrinaVladis [17]3 years ago

4 0

Answer:

$\frac{5\sqrt{5} }{3}$

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Step-by-step explanation:

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In triangle $ABC,$ point $D$ is on $\overline{AC}$ such that $AD = 3CD = 12$. If $\angle ABC = \angle BDA = 90^\circ$, then what

Neporo4naja [7]

Answer:

$BD=4\sqrt{3}\ units$

Step-by-step explanation:

we know that

$AD=12\ units$

$3CD=12$ ----> $CD=4\ units$

see the attached figure to better understand the problem

Triangles ABD and BCD are similar by AA Similarity Theorem

Remember that

If two figures are similar, then the ratio of its corresponding sides is proportional

so

$\frac{BD}{AD}=\frac{CD}{BD}$

substitute the given values

$\frac{BD}{12}=\frac{4}{BD}$

$BD^2=48$

$BD=\sqrt{48}\ units$

simplify

$BD=4\sqrt{3}\ units$

8 0

3 years ago