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MakcuM [25]
3 years ago
13

In which condition the final velocity becomes zero?​

Physics
1 answer:
alexgriva [62]3 years ago
7 0

Answer:

Terminal velocity is achieved, therefore, when the speed of a moving object is no longer increasing or decreasing; the object's acceleration (or deceleration) is zero.

Explanation:

hope it helps you

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two forces have the same magnitude F, what is the angle between the two vectors if their sum has a magnitude of (a) 2F? (b) sqrt
kramer
Ok let me help you with this:
<span>
!n case a) Line both up head-to-tail in a straight line... that's the only way to get a sum 2F. In case b) sqrt(2) is the length of the hypotenuse in a 45 degree triangle, so the vectors must be at 90 degrees to each other in the case of c) lined up head to tail, the only way to get 0 is if they point in opposite direction</span>
5 0
4 years ago
What is meant by components of a vector?
topjm [15]

Answer:

Each part of a two-dimensional vector is known as a component. The components of a vector depict the influence of that vector in a given direction. The components of a vector depict the influence of that vector in a given direction.

Explanation:

hope this helps

3 0
4 years ago
A car weighing 11.1 kN and traveling at 13.4 m/s without negative lift attempts to round an unbanked curve with a radius of 61.0
klasskru [66]

Answer:

Well..

Explanation:

That's impossible. I know because I once weighed 11.1 kN, and I was temporarily immobile. It's probably the same for a car, and therefore it can not be "traveling" anywhere at all.. unless you put the car on an airplane or a boat or something.

8 0
3 years ago
Is this circuit parallel?????? ​
kobusy [5.1K]

Answer:

yes it is parrell

Explanation:

7 0
2 years ago
A bullet is fired vertically upward a velocity of 80m/s to what height will the bullet rise above the point of projection​
frozen [14]

Answer:

The bullet will rise 320 meters above the point of projection.

Explanation:

Assuming that air friction is negligent we can use the kinematic equation:

v_{2} ^2=v_{1} ^2+2(-a)d\\0\frac{m^2}{s^2} =6400\frac{m^2}{s^2} +2(-10\frac{m}{s^2} )d\\-6400\frac{m^2}{s^2} =(-20\frac{m}{s^2}) d\\320m=d

*acceleration is negative (-a) as it is acting in the opposite direction of the motion of the bullet.*

3 0
3 years ago
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