Question

What is the electric field due to a point charge of 20uC at a distance of 1 meter away from it?

Answer 1

The electric field due to a point charge of 20uC at a distance of 1 meter away from it is 180000 $\frac{N}{C}$.

First, you have to know that the space surrounding a load suffers some kind of disturbance, since a load located in that space will suffer a force. The disturbance that this charge creates around it is called an electric field.

In other words, an electric field exists in a certain region of space if, when introducing a charge called witness charge or test charge, it undergoes the action of an electric force.

The electric field E created by the point charge q at any point P, located at a distance r, is defined as:

$E=K\frac{q}{r^{2} }$

where K is the constant of Coulomb's law.

In this case, you know:

• K= 9×10⁹$\frac{Nm^{2} }{C^{2} }$
• q= 20 uC=20×10⁻⁶ C
• r= 1 m

Replacing in the definition of electric field:

$E=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{20x10^{-6} C}{(1 m)^{2} }$

Solving:

E=180000 $\frac{N}{C}$

Finally, the electric field due to a point charge of 20uC at a distance of 1 meter away from it is 180000 $\frac{N}{C}$.

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