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nordsb [41]
3 years ago
9

Find the distance between the two points rounding to the nearest tenth (if necessary).

Mathematics
1 answer:
jek_recluse [69]3 years ago
3 0

Answer:

\displaystyle d \approx 9.8

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

Coordinate Plane

  • Coordinates (x, y)

<u>Algebra II</u>

  • Distance Formula:                                                                                            \displaystyle d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Point (5, 7)

Point (-4, 3)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance<em> d</em>

  1. Substitute in points [Distance Formula]:                                                           \displaystyle d = \sqrt{(-4 - 5)^2 + (3 - 7)^2}
  2. [√Radical] (Parenthesis) Simplify:                                                                    \displaystyle d = \sqrt{(-9)^2 + (-4)^2}
  3. [√Radical] Evaluate exponents:                                                                      \displaystyle d = \sqrt{81 + 16}
  4. [√Radical] Simplify:                                                                                           \displaystyle d = \sqrt{97}
  5. [√Radical] Approximate:                                                                                  \displaystyle d \approx 9.8
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What is the slope of the line that contains the point (13,-2) and (3,-2)
ra1l [238]

The slope of the line that contains the point (13,-2) and (3,-2) is 0

<em><u>Solution:</u></em>

Given that we have to find the slope of the line

The line contains the point (13,-2) and (3,-2)

<em><u>The slope of line is given as:</u></em>

m = \frac{y_2-y_1}{x_2-x_1}

Where, "m" is the slope of line

Here given points are (13,-2) and (3,-2)

(x_1, y_1) = (13, -2)\\\\(x_2, y_2) = (3, -2)

<em><u>Substituting the values in formula, we get,</u></em>

m = \frac{-2-(-2)}{3-13}\\\\m = \frac{-2+2}{3-13}\\\\m = 0

Thus the slope of line is 0

3 0
3 years ago
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