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Natali5045456 [20]
2 years ago
5

Explain how solving $2x<-8$ is different from solving $-2x<8$ .

Mathematics
1 answer:
miv72 [106K]2 years ago
6 0

Answer:

When we divide by a negative value, the sign for the inequality changes.

Step-by-step explanation:

2x < -8, to solve we would divide by 2 and receive x < -4. However, in solving -2x < 8, we would divide by negative 2, which would result in x > -4. Clearly, these sequences provide opposite answers and that is a rule to inequalities, that when dividing by a negative number, we must flip the less than/greater than sign.

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Montano1993 [528]

Answer:

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Step-by-step explanation:

x3+3x2+x-9 is in the division "house" and x-1 is on the outside. xsquare times x equals x cubed. and x square times negative 1 equals -x squsre. put x square on top of the roof. change the signs. the x cubed cancels out. and bring down 2x square from subtracting 3x square and -x square and bring down the x-9. Put 2x on top of the roof too and 2x times x equals 2x square and multiply by -1. U will have 2x square -2x square and -2x plus x which equals -1x cuz the 2x square cancels out. bring down the -9. Now i have -1x-9. Multiply by -1 and put -1 on the roof. -1x+1x cancels out. and -1 times -1 equals positive 1. So -9+1=8. U van do any further cause as soon as the last number is at the end of the roof and u cant go further, ur done dividing. so the answer is x square+2x-1/×-1 +8 as the remainder. hope i helped

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3 years ago
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Answer:

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3 years ago
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Using the rotation R, can you create a function R(ABCD) that is equivalent to the reflection of ABCD across both the x-axis and
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bearhunter [10]
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