A 1500-kilogram car is at rest on a level track. The driver gives the engine gas and the car begins to accelerate forward. The c

Question

3 years ago

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A 1500-kilogram car is at rest on a level track. The driver gives the engine gas and the car begins to accelerate forward. The c

ar moves from 0 meters per second to 27 meters per second in 8 seconds. What is the acceleration of the car? What is the force of the car moving forward?

Physics

1 answer:

Nutka1998 [239] · Answer 1 · 2022-05-27T02:47:24+03:00

1. The acceleration of the car is 3.375 m/s².

2. The force moving the car is 5062.5 N

From the question given above, the following data were obtained:

Mass of car = 1500 Kg

Initial velocity (u) = 0 m/s

Final velocity (v) = 27 m/s

Time (t) = 8 s

<h3>Acceleration (a) =? </h3><h3>Force (F) =? </h3>

<h3>1. Determination of the acceleration </h3>

Initial velocity (u) = 0 m/s

Final velocity (v) = 27 m/s

Time (t) = 8 s

<h3>Acceleration (a) =?</h3>

$a = \frac{v - u}{t} \\\\a = \frac{27 - 0}{8} \\\\a = \frac{27}{8}\\$

Therefore, the acceleration of the car is 3.375 m/s²

<h3>2. Determination of the force moving the car.</h3>

Mass of car = 1500 Kg

Acceleration (a) = 3.375 m/s²

<h3>Force (F) =?</h3>

F = 1500 × 3.375

Therefore, the force moving the car is 5062.5 N

Learn more: brainly.com/question/13001406