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Tema [17]
3 years ago
6

The power of a motorcycle is 150W and the time is 14s. What is the work?

Physics
1 answer:
Artyom0805 [142]3 years ago
8 0
10.7 or round it up to 11
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Which of the following affects the rate constant of a reaction?
Dennis_Churaev [7]
Arrhenius' equation relates the dependence of rate constant of a chemical reaction to the temperature. The equation below is the Arrhenius equation
k = Ae ^{{ \frac{-Ea}{RT} } } where k is the rate constant, T is the absolute temperature. As the temperature of the system increases, the rate constant also increases and vice versa.
3 0
4 years ago
What wavelength ? should the astrophysicist look for to detect a transition of an electron from the n=7 to the n=3 level?
Veseljchak [2.6K]
Using the Debroglies equation,energy can be found,as 1.9773*10*-9
then, energy* wave length= hc
c is the speed of light and is the planks constant.
wave length =1.006*10*-16 m
7 0
3 years ago
A rock is suspended from a string, and it accelerates downward. Which one of the following statements is correct? Group of answe
Tems11 [23]

Answer:

a. The magnitude of the tension in the string is greater than the magnitude of the weight of the rock.

Explanation:

During the motion of the rock while it is in downward motion we can say

T - mg cos\theta = ma_c

since it is performing circular motion so we will have its acceleration towards its center

T = mgcos\theta + ma_c

a_c = \frac{v^2}{L}

T = mgcos\theta + \frac{mv^2}{L}

So at the lowest point of the path we can say

T = mg + \frac{mv^2}{L}

so correct answer is

a. The magnitude of the tension in the string is greater than the magnitude of the weight of the rock.

4 0
3 years ago
This equation goes with which law?
Alchen [17]

Answer:

I think that's Newton's second law of motion

Explanation:

f = m(v-u)

________

t

since a = (v-u)t

f = ma

3 0
3 years ago
Calculate the nuclear binding energy per nucleon for 136^Ba if its nuclear mass is 135.905 amu.
kompoz [17]

Answer:

1.312 x 10⁻¹² J/nucleon

Explanation:

mass of ¹³⁶Ba = 135.905 amu

¹³⁶Ba contain 56 proton and 80 neutron

mass of proton = 1.00728 amu

mass of neutron = 1.00867 amu

mass of ¹³⁶Ba = 56 x  1.00728 amu + 80 x 1.00867 amu

                      = 137.10128 amu

mass defect = 137.10128 - 135.905

                    = 1.19628 amu

mass defect = 1.19628 x 1.66 x 10⁻²⁷ Kg

                     = 1.9858 x 10⁻²⁷ Kg

speed of light = 3 x 10⁸ m/s

binding energy,

E = mass defect x c²

E = 1.9858 x 10⁻²⁷ x (3 x 10⁸)²

E = 17.87 x 10⁻¹¹ J/atom

now,

binding energy per nucleon =\dfrac{17.87\times 10^{-11}}{136}

                                              = 0.1312 x 10⁻¹¹ J/nucleon

                                              = 1.312 x 10⁻¹² J/nucleon

4 0
3 years ago
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