Relate the changes in molecular motion of particles as they change from solid to liquid to gas
1 answer:
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Answer:
m = 4.44 [g]
Explanation:
This is a problem related to heat transfer and thermodynamics. The second law of thermodynamics tells us that heat goes in only one direction, from the highest temperature substance to the lowest temperature. In this case the heat goes from tea to ice. The heat transfer process could be defined as the heat rejection of one body will be equal to the Heat received by another body.
Where:
m = mass = 177[g] = 0.177[kg]
Cp = specific heat = 4186 [J/kg*C]
T_f = 29.1 [°C]
Ti = 31.1 [°C]
Q = 0.177*4186*(29.1 - 31.1)
Q = - 1481.8 [J]
Note: The negative sign means that the heat is rejected.
Recall that the heat rejected is equal to the heat transferred
As the ice is going through a phase change, the fusion latent heat should be used, i.e. when it passes from solid to liquid. The heat transfer for this process is calculated with the following expression.
Qin = m *hf
m = mass of the ice [kg]
hf = Fusion latent heat = 333700 [J/kg]
1481.8 = m * 333700
m = 0.00444 [kg] = 4.44 [g]
Answer:
a) 2.3 m/s^2
b) 33.3 s
c) 803 m
d) 0 m/s
Explanation:
We need to apply the accelerated motion formulas.
The acceleration is given by:
we need to calculate the time the cheetah takes to stop when it starts to decelerate:
We need to calculate the displacement for all of the stages:
stage 1:
stage 2:
stage 3:
The total displacement is given by:
the final velocity of the cheetah is zero because the cheetah decelerates until stop.