A cheetah is resting when a hare traveling in a straight path passes at it's top speed of 25m/s. It takes the cheetah 1.5 second
1 answer:
Answer:
a) 2.3 m/s^2
b) 33.3 s
c) 803 m
d) 0 m/s
Explanation:
We need to apply the accelerated motion formulas.
The acceleration is given by:
we need to calculate the time the cheetah takes to stop when it starts to decelerate:
We need to calculate the displacement for all of the stages:
stage 1:
stage 2:
stage 3:
The total displacement is given by:
the final velocity of the cheetah is zero because the cheetah decelerates until stop.
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Hey there!
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Hope this helps you!
Hope this helps you!