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iren [92.7K]
3 years ago
13

A cheetah is resting when a hare traveling in a straight path passes at it's top speed of 25m/s. It takes the cheetah 1.5 second

s to get up and begin running. The cheetah accelerates to it's top speed of 45m/s is 20 seconds. It can maintain speed for 2 seconds before decelerating at 4 m/s^2.
A. What is the initial acceleration of the cheetah
B. How long does the chase last
C. How far has the cheetah traveled before stopping
D. What is the final velocity of the cheetah?
Physics
1 answer:
timofeeve [1]3 years ago
4 0

Answer:

a) 2.3 m/s^2

b) 33.3 s

c) 803 m

d) 0 m/s

Explanation:

We need to apply the accelerated motion formulas.

The acceleration is given by:

a=\frac{v_f-v_o}{t}\\\\a=\frac{45m/s-0m/s}{20s}\\\\a=2.3m/s^2

we need to calculate the time the cheetah takes to stop when it starts to decelerate:

v=vo+a*t\\\\t=\frac{v-v_o}{a}\\\\t=\frac{0-45m/s}{-4m/s^2}=11.3s\\\\t_t=20s+2s+11.3s=33.3s

We need to calculate the displacement for all of the stages:

stage 1:

x_1=\frac{1}{2}*a*t^2\\\\x_1=\frac{1}{2}*2.3m/s^2*(20)^2\\\\x_1=460m

stage 2:

x_2=v*t\\x_2=45m/s*2s=90m

stage 3:

x_3=v_o*t+\frac{1}{2}*a*t^2\\\\x_3=45m/s*(11.3s)-\frac{1}{2}*4m/s^2*(11.3)^2\\\\x_3=253m

The total displacement is given by:

d=x_1+x_2+x_3\\d=460m+90m+253m=803m

the final velocity of the cheetah is zero because the cheetah decelerates until stop.

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Calculate the pressure exerted on the floor by the boy standing on both feet if the weight of the boy is 40kg. Assume that the a
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Answer:

P = 1333.33 N

Explanation:

The pressure exerted by the boy on the floor can be calculated by the following equation:

P = \frac{F}{A}

where,

P = Pressure exerted by the boy = ?

F = Force Applied = Weight of Boy = 40 kg = 40 N (since 1 kg = 1N)

A = Area of application of force = 2(Area of one show) = 2(6 cm x 25 cm)

A = 2(0.06 m x 0.25 m) = 0.03 m²

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P = \frac{40\ N}{0.03\ m^2}\\\\

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Answer:

0.2 J

Explanation:

The pendulum forms a right triangle, with hypotenuse of 50 cm and base of 30 cm.  The height of this triangle can be found with Pythagorean theorem:

c² = a² + b²

(50 cm)² = a² + (30 cm)²

a = 40 cm

The height of the triangle is 40 cm.  The height of the pendulum when it is at the bottom is 50 cm.  So the end of the pendulum is lifted by 10 cm.  Assuming the mass is concentrated at the end of the pendulum, the potential energy is:

PE = mgh

PE = (0.200 kg) (9.8 N/kg) (0.10 m)

PE = 0.196 J

Rounding to one significant figure, the potential energy is 0.2 J.

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