Answer:
the time taken for the object to fall is 6 s.
Explanation:
Given;
final velocity of the object, v = 58.8 m/s
initial velocity of the object, u = 0
The height of fall of the object is calculated as;
v² = u² + 2gh
v² = 2gh

The time to fall through the height is calculated as;

Therefore, the time taken for the object to fall is 6 s.
Answer:
The magnitude of the radial acceleration is 0.754 rad/s²
Explanation:
Given;
radius of the flywheel, r = 0.2 m
initial angular velocity of the flywheel, 
angular acceleration of the flywheel, a = 0.900 rad/s².
angular distance, θ = 120⁰
the angular distance in radian = 
Apply the following kinematic equation to determine the final angular velocity;

The magnitude of the radial acceleration is calculated as;

Therefore, the magnitude of the radial acceleration is 0.754 rad/s²
Answer:
a) t = 11.407 s, b) x = 175.66 m, v = c) v = 30.80 m / s
Explanation:
a) This is a kinematics exercise, let's write the equation of each vehicle
car
x = x₀ + v₀ t + ½ a t²
Let's fix our reference system at the point where the car is, indicate that the car stops from rest vo = 0
x₀ = v₀ = 0
we substitute
x = ½ a t²
truck
x₂= v₀ t
v₀ = 15.4 m / s
at the point where they are, their positions are equal
½ a t² = vo t
t = 2 vo / a
calculate us
t = 2 15.4 / 2.70
t = 11.407 s
b) the distance to reach it
x = ½ to t²
x = ½ 2.70 11.407²
x = 175.66 m
c) the speed of the car is
v = vo + a t
vo = 0
v = at
v = 2.70 11.407
v = 30.80 m / s
Answer: 

Explanation:
Firstly, let's convert these length to meters
, in order to work with the same units:
a. 400 millimeters

b. 22 kilometers

c. 170 meters
Here the lenght is already in meters
d. 3.3 centimeters

Now that we have all the lengths in meters, we can order them from shortest to longest:

or

Answer:
The velocity is 6 m/s
Explanation:
We use the formula of kinetic energy=
Ec= 1/2 x m x v2
2160 J = 1/2 x 120 kg x v2
v =![\sqrt[n]{x} 2160Joulex2/120kg\\](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%202160Joulex2%2F120kg%5C%5C)
v= 6m/s
1Joule= 1 kgm2/s2