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guapka [62]
3 years ago
12

what is similar about elements in the same group on the periodic table? A) atomic masses B) atomic numbers C) chemical propertie

s D) number of electrons
Physics
1 answer:
ArbitrLikvidat [17]3 years ago
3 0

Answer:

D) Number of electrons.

Explanation:

Elements in the same group on the periodic table has the same number of electrons. These electrons are those involved in  bonding with other atoms to form compounds.

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If an object falls and ends with a velocity of 58.8 m/s, how long was the<br><br> object falling?
tensa zangetsu [6.8K]

Answer:

the time taken for the object to fall is 6 s.

Explanation:

Given;

final velocity of the object, v = 58.8 m/s

initial velocity of the object, u = 0

The height of fall of the object is calculated as;

v² = u² + 2gh

v² = 2gh

h = \frac{v^2}{2g} \\\\h = \frac{(58.8)^2}{2(9.8)} \\\\h = 176.4 \ m

The time to fall through the height is calculated as;

h =ut+  \frac{1}{2} gt^2\\\\h = 0 +  \frac{1}{2} gt^2\\\\h =  \frac{1}{2} gt^2\\\\t= \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 176.4}{9.8} } \\\\t = 6 \ s

Therefore, the time taken for the object to fall is 6 s.

6 0
3 years ago
A flywheel with a radius of 0.200m starts from rest and accelerates with a constant angular acceleration of 0.900rad/s2.
kobusy [5.1K]

Answer:

The magnitude of the radial acceleration is 0.754 rad/s²

Explanation:

Given;

radius of the flywheel, r = 0.2 m

initial angular velocity of the flywheel, \omega_i = 0

angular acceleration of the flywheel, a = 0.900 rad/s².

angular distance, θ = 120⁰

the angular distance in radian = \frac{120}{180} \pi = \frac{2 \pi}{3}  \ rad

Apply the following kinematic equation to determine the final angular velocity;

\omega _f^2 = \omega _i ^2 + 2\alpha \theta\\\\\omega _f^2 = 0 + 2(0.9)(\frac{2\pi}{3} )\\\\\omega _f^2 = 3.7699\\\\\omega _f = \sqrt{ 3.7699} \\\\ \omega _f = 1.942 \ rad/s

The magnitude of the radial acceleration is calculated as;

\alpha _r = \omega ^2r\\\\\alpha _r  = (1.942)^2 (0.2)\\\\\alpha _r  =0.754 \ rad/s^2

Therefore, the magnitude of the radial acceleration is 0.754 rad/s²

4 0
3 years ago
At the instant the traffic light turns green, an automobile that has been waiting at an intersection starts ahead with a constan
liubo4ka [24]

Answer:

a)  t = 11.407 s, b)   x = 175.66 m,  v = c)         v = 30.80 m / s

Explanation:

a) This is a kinematics exercise, let's write the equation of each vehicle

car

          x = x₀ + v₀ t + ½ a t²

Let's fix our reference system at the point where the car is, indicate that the car stops from rest vo = 0

          x₀ = v₀ = 0

we substitute

          x = ½ a t²

truck

         x₂= v₀ t

         v₀ = 15.4 m / s

at the point where they are, their positions are equal

       ½ a t² = vo t

        t = 2 vo / a

calculate us

        t = 2 15.4 / 2.70

        t = 11.407 s

b) the distance to reach it

        x = ½ to t²

        x = ½ 2.70 11.407²

        x = 175.66 m

c)  the speed of the car is

       v = vo + a t

       vo = 0

       v = at

       v = 2.70 11.407

       v = 30.80 m / s

4 0
3 years ago
3. Order the following lengths from shortest to longest.
horrorfan [7]

Answer: d < a < c < b

3.3 cm < 400 mm < 170 m < 22 km

Explanation:

Firstly, let's convert these length to meters m, in order to work with the same units:

a. 400 millimeters

400 mm \frac{1m}{1000 mm}=0.4 m

b. 22 kilometers

22 km \frac{1000m}{1 km}=22000 m

c. 170 meters

Here the lenght is already in meters

d. 3.3 centimeters

3.3 cm \frac{1m}{100 cm}=0.033 m

Now that we have all the lengths in meters, we can order them from shortest to longest:

0.033 m < 0.4 m < 170 m < 22000 m

or

d < a < c < b

7 0
4 years ago
An object with a kinetic energy of 2160 J has a new mass of 120kg. What is it's velocity?
nadya68 [22]

Answer:

The velocity is 6 m/s

Explanation:

We use the formula of kinetic energy=

Ec= 1/2 x m  x v2

2160 J = 1/2 x 120 kg x v2

v =\sqrt[n]{x} 2160Joulex2/120kg\\

v= 6m/s

1Joule= 1 kgm2/s2

4 0
3 years ago
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