From the transitions of ice to water, water to steam, steam to water,
or water to ice, mass doesn't change.
Answer:
It will take 60 hours to pass your area
Explanation:
From the question we are told that
The the distance of wispy cirrus clouds is 
The slope is given as 
The speed is 
Since the slope is 1:300 which indicates the change in the distance of the wispy cirrus clouds overhead to the distance of the warm front
Now if
1 km → 300 km
Then
→ x km
Cross multiplying and making x the subject
Velocity is mathematically denoted as
Now making time the subject
Now substituting values we have
First off, Newton's second law<span> of motion is the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
So therefore, it would be a force is being applied to the mass</span>
The ratio of the kinetic energy of the block/bullet system immediately after the collision to the initial kinetic energy of the bullet is 0.78 %.
<h3>Final velocity of the block/bullet system</h3>
Apply the principle of conservation of energy to determine the final velocity of the block/bullet system.
K.E = P.E
¹/₂mv² = mgh
¹/₂v² = gh
v² = 2gh
v = √2gh
where;
- h is the maximum height reached by the system
- v is the initial velocity of the system
v = √(2 x 9.8 x 1.1)
v = 4.64 m/s
<h3>Initial velocity of the bullet</h3>
Apply the principle of conservation of linear momentum.
m₁u₁ + m₂u₂ = v(m₁ + m₂)
where;
- u₁ is the initial velocity of the bullet
- u₂ is the initial velocity of the block
- v is the final velocity after collision
- m₁ is mass bullet
- m₂ is mass of block
(0.0075)u₁ + (0.95)(0) = 4.64(0.0075 + 0.95)
0.0075u₁ = 4.4428
u₁ = 4.4428/0.0075
u₁ = 592.37 m/s
<h3>Initial kinetic energy of the bullet</h3>
K.Ei = ¹/₂m₁u₁²
K.Ei = ¹/₂(0.0075)(592.37)²
K.Ei = 1,315.88 J
<h3>Final kinetic energy of the block/bullet system</h3>
K.Ef = ¹/₂(m₁ + m₂)v²
K.Ef = ¹/₂(0.0075 + 0.95)(4.64)²
K.Ef = 10.31 J
<h3>Ratio of final kinetic energy to initial kinetic energy</h3>
= K.Ef/K.Ei x 100%
= (10.31 / 1,315.88) x 100%
= 0.78 %
Learn more about kinetic energy here: brainly.com/question/25959744
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Answer:
<h2>Magnetic field strength in that region is 1.2 T</h2>
Explanation:
As we know by the formula of radius of charge moving in external field is given as
so we will have
now we have
now we have
