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Ierofanga [76]
3 years ago
6

An atom of the element chromium has an atomic number of 24 and a mass number of 52. How many electrons are in an uncharged atom

of chromium?
Physics
2 answers:
zubka84 [21]3 years ago
4 0

<span>Chromium is represented by the element Cr with an atomic number of 24 and a molar mass of 52 gram per mole. The number of protons in the Chromium atom is the atomic number, so it has 24 protons. And the protons of chromium atom is equal to the number of electrons, so 24 electrons.</span>

ludmilkaskok [199]3 years ago
3 0

Answer:

24

Explanation:

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Perspective is the evaluation or analysis of something, the way we think.
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AnnZ [28]

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7 0
3 years ago
If you can answer both, please do. But if you can't, just answer one.
Setler [38]

Answer:

1.The force required to stop the shopping cart is, F = 12.25 N

Explanation:

Given data,

The mass of the shopping cart, m = 7 kg

The initial velocity of the shopping cart, u = 3.5 m/s

The final velocity of the shopping cart, v = 0 m/s

The time period of acceleration, t = 2 s

The change in momentum of the cart,

                                      p = m(u - v)

                                         = 7 (3.5 - 0)

                                         = 24.5 kg m/s

The force is defined as the rate of change of momentum. To stop the shopping cart, the force required is given by the formula

                                           F = p / t

                                               = 24.5 / 2

                                               = 12.25 N

Hence, the force required to stop the shopping cart is, F = 12.25 N

2.

We have: F = m × v/t

Here, m = 8500 Kg

v = 20 m/s

t = 10 s

Substitute their values into the expression,  

F = 8500 × 20/10

F = 8500 × 2

F = 17000 N

In short, final answer would be 17000 N

Hope this helps!!

7 0
3 years ago
A block is at rest on the incline shown in the gure. The coefficients of static and kinetic friction are 0.6 and 0.51, respec- t
Alekssandra [29.7K]

Normal reaction force on the block while it is at rest on the inclined plane is given as

F_n = mgcos\theta

here we know that

m = 46 kg

\theta = 29^o

now we will have

F_n = 46*9.8*cos29 = 394.3 N

now the limiting friction or maximum value of static friction on the block will be given as

F_s = \mu_s * F_n

F_s = 0.6 * 394.3 = 236.56 N

Above value is the maximum value of force at which block will not slide

Now the weight of the block which is parallel to inclined plane is given as

F_{||} = mg sin\theta

here we know that

F_{||} = 46*9.8 sin29 = 218.55 N

Now since the weight of the block here is less than the value of limiting friction force and also the block is at rest then the frictional force on the block is static friction and it will just counter balance the weight of the block along the inclined plane.

So here <u>friction force on the given block will be same as its component on weight which is 218.55 N</u>

5 0
3 years ago
Hello, I need help answering and explaining the question in the attached image. It includes the figures plus the question and th
Flauer [41]

Answer:

d.

Explanation:

Since the dart's initial speed v at angle has both vertical and horizontal components v₀sinθ and v₀cosθ respectively, the vertical component of the speed continues to decrease until it hits the target. It's displacement ,s is gotten from

s = y - y₀ = (v₀sinθ)t - 1/2gt² where y₀ = 0 m

y - 0 = (v₀sinθ)t - 1/2gt²

y = (v₀sinθ)t - 1/2gt²

which is the parabolic equation for the displacement of the dart.

Note that the horizontal component of the dart's velocity does not change during its motion.

Since the target falls vertically, with initial velocity u = 0 (since it was stationary before the string cut), it's displacement ,s' is gotten from

s' = y - y₀' = ut - 1/2gt² where y₀' = initial height of target above the ground

= (0 m/s)t - 1/2gt²

= 0 - 1/2gt²

y - y₀' = - 1/2gt²

y = y₀' - 1/2gt²

which is the parabolic equation for the displacement of the target.

The equation for both the displacement of the dart and the target can only be gotten if we considered vertical motion. So, the displacement component of both the dart and target are both vertical.

So, the answer is d.

8 0
3 years ago
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