You would benefit from your own handled problem because you solved a problem you had.
i’m pretty sure that’s it, going off the info i had.
Answer:
B. tablespoon
Explanation:
Considering the question given, a mole of water is small compare to the options given from the question aside the table spoon.
A mole of water is just 18g and that's equivalent to 18 mL.
18 mL of water will fill a table spoon but not a cup which is about 237mL. The wheel barrow and gallon bucket have larger volumes of which 18 mL of water will never fill them.
So, a mole of water can successfully fill a table spoon.
B: <span>It contains all of the wavelengths of the visible light spectrum.
Hope this helps mate =)</span>
Answer:
the decrease in energy is due to a transformational in internal energy of the body in the rebound.
Explanation:
For this exercise we can calculate the initial and final mechanical energy
Em₀ = U = m g y₁
= U = m g y₂
we look for the variation of the energy
ΔEm = Em_{f} - Em₀
ΔEm = m g (y_{f} -y₀)
ΔEm = m g (0.86 -1.2)
ΔEm = -3.332 m
We can see that there is a decrease in mechanical energy, this is transformed into internal energy of the ball during the impact with the ground, this energy can be formed by several factors such as a part of the friction with the surface, an increase in body temperature or a deformation of the body; there may be a contribution from several of these factors.
In conclusion the decrease in energy is due to a transformational in internal energy of the body in the rebound.
a) 0.26 h
b) 71.4 km
Explanation:
a)
In order to solve the problem, we have to know what is the final velocity of the car.
Here, we assume that the final velocity reached by the car is

Therefore, we can find the time taken by the car to reach this velocity by using the suvat equation:

where:
u = 250 km/h is the initial velocity
is the acceleration of the car
v = 300 km/h is the final velocity
t is the time
Solving for t, we find:

b)
In order to find the distance covered by the car, we can use the following suvat equation:

where:
s is the distance covered
u is the initial velocity
a is the acceleration
t is the time
For the car in this problem, we have:
u = 250 km/h
t = 0.26 h (calculated in part a)

Therefore, the distance covered is
