Answer:
Explanation:
Given that,
The absolute pressure inside the champagne is 6 times atmospheric pressure
Atmospheric pressure is 101,325 N/m²
So, the absolute pressure in the champagne is
P_abs = 6 × P_atm
P_abs = 6 × 101,325
P_abs = 607,950 N/m²
If the cork of the champagne has a mass of
M = 7.5g
M = 7.5 / 1000 = 0.0075 kg
The diameter of the cork is 18mm, It is no possible for the diameter to be 18m, so I assumed it is 18mm
d = 18mm = 0.018m
The area of the circle will be
Area = πd² / 4
Area = π × 0.018² / 4
Area = 2.545 × 10^-4 m²
We know that,
Pressure = Force / Area
Then,
Force = Pressure × Area
Force = 607,950 × 2.545 × 10^-4
Force = 154.723 N
Then, from newton second law,
F = ma
a = F / m
a = 154.723 / 0.0075
a = 20629.77 m/s²
a ≈ 20,630 m/s²
The acceleration of the cork is 20,630 m/s²
