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Nostrana [21]
3 years ago
15

When compared to others, how is a greater velocity represented on a motion map?

Physics
2 answers:
melomori [17]3 years ago
7 0

Answer:

b, with longer vectors! I couldn't find an answer so I guessed and got it correct.

Explanation:

Rina8888 [55]3 years ago
3 0

Explanation:

At each position, the object's velocity is represented by a vector. If the car were traveling at greater velocity, the strobe photo might look like this: The corresponding motion map has the points spaced farther apart, and the velocity vectors are longer, implying that the car is moving faster.

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The ________ is the maximum value or strength of the signal over time; typically this value is measured in volts.
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or rms value..root mean square value
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3 years ago
What is the average speed of the car from 0 to 10 s?
blagie [28]

the average of the speed is 60

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Hope this helps!! All credit goes to Google though

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4 years ago
Read 2 more answers
Which type of ladder has flat steps, hinged back, self-supporting, and non-adjustable?
il63 [147K]

Answer:  Step Ladders

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<u>Step ladders :</u>

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5 0
3 years ago
A solid conducting sphere has net positive charge and radius r = 0.800 m . At a point 1.20 m from the center of the sphere, the
Serga [27]

here we have to calculate the net positive charge present on he surface  of the conducting  sphere.

as the sphere is a conducting one the,the charge will be stored on its surface.

though the charge is present at the surface,still it will behave just like the total charge is concentrated at the centre of the sphere.

the electric field at outside of the sphere is E=\frac{1}{4\pi\epsilon} \frac{q}{r^2}

as E= \frac{-dv}{dr}

so V=\frac{1}{4\pi\epsilon} \frac{q}{r}

here V=27 volt,radius of sphere is 0.800 m and the point at which the potential is considered is at 1.20 m from th centre of the sphere.hence the point is at the outside of the sphere .

hence we have 27=\frac{1}{4\pi\epsilon} \frac{q}{1.20}

                            q=27×\frac{1}{9*10^{9} }* 1.20 coulomb

                                =3.6×10^{-9} coulomb [ans]

5 0
3 years ago
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