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2 years ago

Bella received $1,200 after winning a national mathematics competition. She plans to invest this money for 5 years.

Mathematics

1 answer:

vredina [299]2 years ago

6 0

Answer:

Step-by-step explanation:

A. 1200(1.078)⁵ = 1746.928179

B. 1200(1+.072*5)= 1632

Option A

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In an insect colony there are 270 insects after 9 days. If there were initially 80 insects how long will it take the population

Semenov [28]

Answer:

The time it will take the population to grow to 800 insects is 17 days.

Step-by-step explanation:

The growth function of the insects is exponential.

The exponential growth function is:

$y=a(1+r)^{t}$

Here,

y = final value

a = initial value

r = growth rate

t = time taken

It is provided that there were 270 insects after 9 days and initially there were 80 insects.

Compute the value of r as follows:

$y=a(1+r)^{t}\\\\270=80(1+r)^{9}\\\\3.375=(1+r)^{9}\\\\\ln(3.375)=9\cdot \ln(1+r)\\\\0.135155=\ln(1+r)\\\\1+r=1.14471\\\\r=0.145$

Now, compute the time it will take the population to grow to 800 insects as follows:

$800=80(1+0.145)^{t}\\\\10=(1.145)^{t}\\\\\ln(10)=t\cdot \ln(1.145)\\\\t=17.00522\\\\t\approx 17$

Thus, the time it will take the population to grow to 800 insects is 17 days.

7 0

2 years ago

Here are the scores of students on a history test. 55, 56, 57, 58, 58, 64, 65, 66, 69, 75, 77, 78, 81, 81, 85, 86, 91. Create a

Anarel [89]

The first thing you need to do is get the median of the whole set.

The median is the center so since there are 17 numbers the center is 69 and 69 is Q2

Next we need to find Q1 Q3 and Q4 Also, are whiskers are below.
Whisker minimum = 55
Whisker maximum = 91

Now to find Q1 we have to get the median of the first half of the data.
We need to get the median of the following data set.
55, 56, 57, 58, 58, 64, 65, 66

(58+58) / 2 = 58
Q1 = 58

Now we need to find Q3. To do that we get the median of the second half of the data.
75, 77, 78, 81, 81, 85, 86, 91.
(81 + 81) / 2 = 81
Q3 = 81

Now we have all our quartiles and whiskers, which are below, it is time to create our box and whisker plot. Note, create a horizontal or vertical number line with appropriate data. Also the box part is from Q1 to Q3 and your whiskers goes from your minimum to your box and from your maximum to your box.

Whisker Minimum = 55
Q1 = 58
Q2 = 69
Q3 = 81
Whisker Maximum = 91

6 0

2 years ago

Determine if direct variation x-2y=0

Fofino [41]

Answer:

x-2y=0 is a direct variation

Step-by-step explanation:

Direct variation is of the form

y= kx

Can we get the equation in that form

x-2y =0

Add 2y to each side

x-2y+2y =0_2y

x=2y

Divide each side by 2

x/2 = 2y/2

1/2x =y

Flip the sides

y = 1/2x

This is of the form y= kx where k = 1/2

x-2y=0 is a direct variation

3 0

2 years ago

Is (2, 3) a solution to this system of equations? y : = x + 2 -1 y = -x + 4 2

MakcuM [25]

Step-by-step explanation:

so blue and pink = purple Yellow and red = orange

8 0

1 year ago

Juan tiene cubos azules de 55 mm de arista y cubos rojos de 45 mm de arista. Los apila en dos columnas, una de cada color ; quie

balu736 [363]

the question in English

Juan has blue cubes with a 55 mm edge and red cubes with a 45 mm edge. He stacks them in two columns, one of each color; he wants the two columns to be the same height. How many cubes does he need, as a minimum, of each color?

Let

x---------> the number of blue cubes

y--------> the number of red cubes

we know that

Juan wants that the two columns to be the same height

$55x=45y$

solve for y

$y=\frac{55}{45}x$

I proceed to calculate a table, assuming values of x to calculate the value of y. When the values of x and y are whole numbers, I will have found the solution.

the table in the attached figure

therefore

the answer is

9 blue cubes

11 red cubes

7 0

2 years ago