3 years ago

The lenght of sydney's tennis racket is 2 rulers long. How many feet long is sydeney's tennis racket

Mathematics

1 answer:

Katyanochek1 [597]3 years ago

3 0

24 feet wrong cause 1 ruler is 12 in so add 12to12

You might be interested in

A company logo is made up of a square and three identical triangles. what is the area of the logo?enter your answer in the box.

amid [387]

91 it is the right answer

5 0

3 years ago

Read 2 more answers

a business shows a profit of $110 for selling 20 leather wallets how much profit would the business make if they sold 35 wallets

mafiozo [28]

Answer:

They would get 192.5

Step-by-step explanation:

First we need to find how much it cost per 1 so you will need to dovide 110 by 20 which equal 5.5

Then you will multiply 5.5*35 and get 192.5

8 0

3 years ago

Ned took a test with 20 questions. He lost 3 points for each of the 5 questions he got wrong and earned an additional 12 points

marusya05 [52]

Answer:

He lost 15 points and recieved 12 points back now he missing 3 points

8 0

3 years ago

A researcher posts an online advertisement offering $25 in exchange for participation in a short study. The researcher accepts t

valina [46]

Answer:

Step-by-step explanation:

The study only consisted of 10 people. 10 people are not enough to come to a concrete conclusion for a project. Hope this helps!!

8 0

3 years ago

Read 2 more answers

When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%. Let

kupik [55]

Answer:

(a) 0.873 (b) 0.007 (c) 0.715 (d) 0.277 (e) 1.25 and 1.09

Step-by-step explanation:

The probability that the random variable X takes the value x is given by P(X=x) = $25Cx 0.05^x0.95^{25-x}$ . Then,

(a) $P(X\leq) = (25C0)(0.05^0)(0.95^{25}) + (25C1)(0.05^1)(0.95^{24}) + (25C2)(0.05^2)(0.95^{23})= 0.873$

(b) $P(X\geq5) = 1-P(X\leq4) = 1 - (0.873 + (25C3)(0.05^3)(0.95^{22}) + (25C4)(0.05^4)(0.95^{21})) = 1 - (0.873 + 0.12) = 0.007$

(c) $P(1\leqX\leq4) = (25C1)(0.05^1)(0.95^{24}) + (25C2)(0.05^2)(0.95^{23}) + (25C3)(0.05^3)(0.95^{22}) + (25C4)(0.05^4)(0.95^{21}) = 0.715$

(d) $P(X=0) = (25C0)(0.05^0)(0.95^{25}) = 0.277$

(e) E(X) = np = (25)(0.05) = 1.25 and $Sd(X) = \sqrt{Var(X)} = \sqrt{np(1-p)} = 1.09$

8 0

2 years ago