Answer:
Coefficient of skewness = 0.5785
Population standard deviation = 88.154
Step-by-step explanation:
Given the data:
Month Jan Feb Mar Apr May Jun Jul
Unit Sales 314 285 158 482 284 310 281
Reordered data : 158, 281, 284, 285, 310, 314, 482
The population mean of the data :
Mean, μ = Σx / n = 2114 / 7 = 302
The median :
1/2(n+1)th term
n = 7
1/2(8)th term
Median = 4th term = 285
The population standard deviation, s :
s = √(Σ(x - μ)²/n)
s = √[(158-302)^2 + (281-302)^2 + (284-302)^2 + (285-302)^2 + (310-302)^2 + (314-302)^2 + (482-302)^2] / 7
s= √(54398 / 7)
s = √7771.1428
s = 88.154
The Pearson Coefficient of skewness :
[3(μ - median)] / s
3(302 - 285) / 88.154
3(17) / 88.154
51 / 88.154
= 0.5785
Answer: The answer for the blank is domain.
Step-by-step explanation: Domain is the input of a function, and range is the output.
The formula would be a=7h+5m.
interesting.
Well
You want to calculate the interest on $1000 at 3.5% interest per month after 3 year(s).
The formula we'll use for this is the simple interest formula, or:
Where: P is the principal amount, $1000.00.
r is the interest rate, 3.5% per month, or in decimal form, 3.5/100=0.035.
t is the time involved, 3....year(s) time periods.
Since your interest rate is "per month" and you gave your time interval in "year(s)" we need to convert your time interval into "month" as well.
Do this by multiplying your time, 3 year(s), by 12, since there's 12 months in 1 year.
So, t is 36....month time periods.
To find the simple interest, we multiply 1000 × 0.035 × 36 to get that:
The interest is: $1260.00
Hope i could help
Answer:
I am stuck on this problem too. Is it on eacxt path.
Step-by-step explanation: