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vichka [17]
3 years ago
6

A car is traveling at 20 m/s and a dog runs out in front

Physics
1 answer:
Pani-rosa [81]3 years ago
8 0

Answer:

Below

Explanation:

To find the acceleration of the car you can use this formula and rearrange :

     vf = vi + at

We know that our time is 2 seconds, our initial velocity, vi, is 20 m/s, and our final velocity vf is 0 because the car comes to a stop before hitting the dog.

So we can just go ahead and plug in these values into the equation above :

     0m/s = 20m/s + (a)(2s)

     -20m/s = 2s(a)

Divide both sides by 2

     -10m/s^2 = a

Therefore the acceleration of the car is -10m/s^2 [forward]

     You could also write this as 10m/s^2 [back]

Hope this helps! Best of luck <3

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-47.04

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At 19°C, a rod is exactly 19.11 cm long on a steel ruler. Both the rod and the ruler are placed in an oven at 280°C, where the r
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Answer:

\alpha = 4.12 \times 10^{-5} per Degree C

Explanation:

As we know that when we increase the temperature of the rod and the ruler then in that case there will be change in the length of the both.

Due to this the ruler measurement is different from actual length of the rod

So by thermal expansion we know that

L = L_o(1 +\alpha \Delta T)

L = 19.11 (1 + \alpha(280 - 19))

L = 19.11(1 + 261\alpha)

Now for length of unit division of steel scale

1 unit = 1( 1 + \alpha_s \Delta T)

1 unit = (1 + (11 \times 10^{-6})(280 - 19))

1 unit = 1.0029

now the measured length from the scale is given as

L_{measured} = \frac{L}{1.0029}

L_{measured} = \frac{19.11(1 + 261\alpha)}{1.0029}

19.26 = \frac{19.11(1 + 261\alpha)}{1.0029}

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8 0
3 years ago
An electric generator contains a coil of 140 turns of wire, each forming a rectangular loop 71.2 cm by 22.6 cm. The coil is plac
Montano1993 [528]

Answer:

11405Volt

Explanation:

To solve this problem it is necessary to use the concept related to induced voltage or electromotive force measured in volts. Through this force it is possible to maintain a potential difference between two points in an open circuit or to produce an electric current in a closed circuit.

The equation that allows the calculation of this voltage is given by,

\epsilon = BAN \omega

Where

B = Magnetic field

A= Area

N = Number of loops

\omega= Angular velocity

Our values previously given are:

N = 140

A = 71.2*10^{-2}m*22.6*10^{-2}m=0.1609m^2

B = 4.32 T

\omega = 1120 rev / min

We need convert the angular velocity to international system, then

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Applying the equation for emf, we replace the values and we will obtain the value.

\epsilon = BAN \omega

\epsilon = (4.32)(0.1609)(140)*117.2

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4 years ago
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