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Schach [20]
3 years ago
5

A pumpkin is thrown horizontally off of a building at a speed of 2.5 m/s and travels a horizontal distance of 12 m before hittin

g the ground.
What was the initial height of the pumpkin?
What was the final vertical velocity of the pumpkin?
Physics
1 answer:
LUCKY_DIMON [66]3 years ago
8 0

Answer:

-47.04

Explanation:

Divide 12 m by 2.5 m/s which equals 4.8s

And then use 4.8s to multiply it with -9.8

4.8(-9.8)= -47.04 m/s

Hope this helped!! :)

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A child's top is held in place upright on a frictionless surface. The axle has a radius of ????=3.21 mm . Two strings are wrappe
tekilochka [14]

Answer:

Angular momentum, L=6.47\times 10^{-3}\ m

Explanation:

It is given that,

Radius of the axle, r=3.21\ mm=3.21\times 10^{-3}\ m

Tension acting on the top, T = 3.15 N

Time taken by the string to unwind, t = 0.32 s

We know that the rate of change of angular momentum is equal to the torque acting on the torque. The relation is given by :

\tau=\dfrac{dL}{dt}

Torque acting on the top is given by :

\tau=F\times r

Here, F is the tension acting on it. Torque acting on the top is given by :

\tau=2F\times r

2T\times r=\dfrac{L}{t}

L=2T\times r \times t

L=2\times 3.15\times 3.21\times 10^{-3}\times 0.32

L=6.47\times 10^{-3}\ m

So, the angular momentum acquired by the top is 6.47\times 10^{-3}\ m. Hence, this is the required solution.

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4 years ago
Earth is slightly closer to the sun in january than in july. How does the area swept out by earth’s orbit around the sun during
Anna007 [38]

This is because both areas are the same.

8 0
3 years ago
In order to increase the amount of work completed, it is necessary to decrease the force applied to an object. decrease the time
wlad13 [49]
<span> <span> The answer to your question is: increase the force applied to the object.

Two items are provided as a basis for that conclusion:
1. According to Newton's Second Law of Motion, the formula for finding force is: F = ma
where F is the force,
m is the mass of an object,
and a is the acceleration of the object.

And 2: work = force x distance or W = F x d.</span></span>
5 0
3 years ago
Read 2 more answers
A ball of mass 0.15 kg is dropped from rest from a height of 1.25 m. It rebounds from the floor to reach a height of 0.960 m. b)
Art [367]

Answer:

Explanation:

If v be the velocity just after the rebound

Kinetic energy will be converted into potential energy

1/2 m v² = mgh

v² = 2gh

v = √ 2gh

= √ 2 x 9.8 x .96

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4 0
3 years ago
Calculate the work function that requires a 475 nm photon to eject an electron of 1.25 eV.
lapo4ka [179]
The work function has the formula
E = h v

where
E is the energy
h is the constant
v is the frequency

Since the given is wavelength, we use the relationship between frequency and wavelength
v = c / λ
where
c is the speed of light
<span>λ is the wavelength
</span>
So.
E = h c / <span>λ
h = E</span><span>λ / c = 1.25 eV (475x10-9m) / (3x10^8 m/s)
h = 1.9792 x 10^-15

The work function is:
E = 1.9792 x 10-15 v

</span>
3 0
3 years ago
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