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gulaghasi [49]
2 years ago
13

What is 820,947,236 write in words​

Mathematics
2 answers:
Arisa [49]2 years ago
8 0

Answer:

Eight Hundred Twenty Million, Nine Hundred Forty-Seven Thousand, Two Hundred Thirty-Six

Step-by-step explanation:

olga2289 [7]2 years ago
7 0

Answer: eight hundred twenty million, nine hundred forty-seven thousand, and two hundred thirty-six

Step-by-step explanation:

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Pls i need this asap
Goryan [66]

Answer:

It would have to be (C) 50.27 because 25 is too short for a diameter of 8 seeing it would be 8x4 to get 32 in which 25 is not long enough for. So the answer is C.

6 0
2 years ago
Lilian says that 25% of a number will always be less than 75% of any other number. Complete one inequality to support Lillian's
rjkz [21]
She is incorrect cause if we take the number 20 and take 25% of it it equals 5 so now 20 is only 15. They if we take 75% away from 20 is equals 15 so then we only have 5 from 20 left. Therefore she’s incorrect because 75% leaves 5/20 and 25% leaves 15/20. Hope that makes sense.
6 0
3 years ago
Help with this question please!
Anton [14]

∠1 and ∠2 are alternate exterior angles where transversal BE crosses parallel lines AC and DF, therefore they are equal. ∠2 and ∠3 are opposite angles of a parallelogram, therefore they are equal.

... ∠1 = ∠2

... 3x -5 = 2x +15 . . . . substitute the given values

... x = 20 . . . . . . . . . . . add 5-2x

The measures of angles 1, 2, and 3 are 2·20+15 = 55 . . . degrees.

5 0
3 years ago
A spherical balloon has a circumference of 23 cm. What is the approximate surface area of the balloon to the nearest square cent
Bad White [126]
168cm2
Let r cm be the radius of the balloon, then 
<span>2pi(r)=23=>r=23/(2pi) </span>
<span>The surface area= </span>
<span>4pi(r^2)= </span>
<span>4pi[23/2pi)]^2= </span>
<span>(23^2)/pi=168.386 cm^2 </span>
<span>approximately.</span>
7 0
3 years ago
Feven can that you ply two wars will the same base, the new exponent is the product
lorasvet [3.4K]
3.3=3 since the denominator is greater than the numerator
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