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leonid [27]
3 years ago
5

Question 3

Mathematics
1 answer:
REY [17]3 years ago
4 0
<span>Question 3 
Solve for d.

13d + 4 = 43
13d = 39
    d = 3

answer
A. 3

</span><span>Question 4 
Solve for r.

4r - 6 = 30
4r = 36
  r = 9

answer

D. 9
</span>

<span>Question 5 
Solve for u.

126 = 6u
u = 126/6
u = 21

answer

B. 21

</span>
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Which is greater 7/8 or 5/10
Sloan [31]
Find a common denominator 7/8 = 35/40 and 5/10 = 20/40. Also 7/8 is almost a whole and 5/10 is half. 7/8 is greater.
7 0
3 years ago
Read 2 more answers
A test of H0: p = 0.5 versus Ha: p &gt; 0.5 has the test statistic z = 1.15. Part A: What conclusion can you draw at the 5% sign
Nadya [2.5K]

Answer:

Part A: The null hypothesis failed to be rejected.

Part B: The null hypothesis failed to be rejected.

Step-by-step explanation:

We have an hypothesis test with null and alternative hypothesis H0: p = 0.5 versus Ha: p > 0.5, which has the test statistic z=1.15.

Part A: If the significance level is 0.05, the conclusion depends on the P-value.

If the P-value is below 5%, the null hypothesis is rejected.

The P-value for this right-tailed tes and z=1.15 is:

P-value=P(z>1.15)=0.125

The P-value is bigger than the significance level, so the effect is not significant and the null hypothesis is failed to be rejected.

Part B: In this case, the significance level is 0.01 and, as the alternative hypothesis is defined with an unequal sign, the test is two-tailed.

This changes the way we calculate the P-value, as we need to compute the two tails.

The P-value is:

P-value=2P(z>1.15)=0.25

The P-value is bigger than the significance level, so the effect is not significant and the null hypothesis is failed to be rejected.

5 0
3 years ago
Find the derivative by definition of the function 2x^3-x^2+4
nikklg [1K]
The answer is 6x^2-2x
6 0
3 years ago
A beach has to enclose a rectangular area, because some endangered species are nesting there. They have 200 feet of rope to rope
kkurt [141]
Area is equal to length times width. The perimeter (the amount of rope) has to equal twice the length added to twice the width so we're left with:
A = l * w
200 = 2l + 2w
solve for either l or w
l = 100 - w
plug into the area equation to get one equation with two variables
A = w(100 - w)
A = -w^2 + 100w
take the derivative
A' = -2w + 100
set the derivative equal to zero
0 = -2w + 100
2w = 100
w = 50
This is the width that maximizes the area
with a width of 50, the length must also be 50 to have a perimeter of 200
therefore, they can rope up to 50 * 50 = 2500 ft^2
6 0
3 years ago
Consider a set of one-dimensional points: 6, 12, 18, 24, 30, 42, 48.
Vinvika [58]

Answer:

1) With initial centroids 10-40, final clusters are

first cluster (6,12,18,24,30)

second cluster (42,48)

And the Sum of Squared Errors (SSE) for the clustering result is 378

2) With initial centroids 10-20, final clusters are

first cluster (6,12,18,24)  

second cluster (30,42,48)

And the Sum of Squared Errors (SSE) for the clustering result is 348

Step-by-step explanation:

K-means works as follows

  • the points will be clustered according to their distance to the centroids.
  • Then centroids are updated as the cluster means.
  • This process continues until clusters doesn't change anymore

1)  <u><em>initial centroids</em></u> 10-40

first cluster (6,12,18,24)  mean:15

second cluster (30,42,48) mean:40

<u><em>new centroids</em></u> 15-40

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

<u><em>final centroids</em></u> 18-45

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

Sum of Squared errors = (18-6)^{2}+(18-12)^{2}+(18-18)^{2}+(18-24)^{2}+(18-30)^{2}+(45-42)^{2}+(45-48)^{2}=378

2)<u><em>initial centroids</em></u> 10-20

first cluster (6,12)  mean:9

second cluster (18,24,30,42,48)  mean:32.4

<u><em>new centroids</em></u> 9-32.4

first cluster (6,12,18) mean:12

second cluster (24,30,42,48) mean:36

<u><em>new centroids</em></u> 12-36

first cluster (6,12,18,24) mean:15

second cluster (30,42,48) mean:40

<u><em>final centroids</em></u> 15-40

first cluster (6,12,18,24) mean:15  

second cluster (30,42,48) mean:40

Sum of Squared errors = (15-6)^{2}+(15-12)^{2}+(15-18)^{2}+(15-24)^{2}+(40-30)^{2}+(40-42)^{2}+(40-48)^{2}=348

6 0
3 years ago
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