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3 years ago

If one liquid is poured into another liquid, which would demonstrate transfer of energy in the form of heat?

Physics

1 answer:

klemol [59]3 years ago

5 0

Answer:

I think I'd say B I'm not very Sure if I'm right.

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What effect does the sun have on Earth's tides? A. The pull of the sun cancels the pull of the moon when they are on opposite si

Kisachek [45]

Answer:

Explanation:

because two vectors which align in the same line adds one to another

6 0

3 years ago

A car is traveling with a velocity of 24.4 m/s. It accelerates at a constant rate of 3.2m/s2. If the acceleration lasts for 5.6

larisa86 [58]

Answer: 42.32 ms-1

Explanation:

v = u+ at

v = 24.4 + ( 3.2×5.6)

v = 42.32 ms-1

6 0

3 years ago

A ball travels with velocity given by Error converting from MathML to accessible text., with wind blowing in the direction given

KengaRu [80]

Answer: The magnitude of the velocity = 2/5 m/s

Explanation:

In this question, the magnitude of the velocity is the product of the magnitude of the displacement vector and the magnitude of the component of the velocity that acts in the direction of displacement.

This will be a scalar projection of V onto X

Please find the attached files for the solution

5 0

3 years ago

Two equally charged insulating balls each weigh 0.16 g and hang from a common point by identical threads 35 cm long. The balls r

Dafna11 [192]

Answer:

Q₁ = Q₂ = 8.84 x 10⁻⁹ C

Explanation:

given,

mass of ball, m = 0.16 g = 1.6 x 10⁻⁴ Kg

ball each other, r = 6.8 cm

Weight of the ball

F_w = m g

F_w = 1.6 x 10⁻⁴ x 9.8

F_w = 1.56 x 10⁻³ N

The tension in each string is a force directed along the length of the string and is the hypotenuse of a right triangle.

we have to find the horizontal component of the forces.

The length of the string,L is 35 cm so, it will be the hypotenuse.

θ be the angle made with imaginary vertical line and the string.

now,

$sin \theta = \dfrac{r\2}{L}$

$sin \theta = \dfrac{3.4}{35}$

θ = 5.57°

horizontal component of the force = ?

vertical component of force,F_v = 1.56 x 10⁻³ N

$tan\theta = \dfrac{F_H}{F_v}$

$tan(5.57^0) = \dfrac{F_H}{1.56\times 10^{-3}}$

F_h = 1.52 x 10⁻⁴ N

now, each ball will be repelled by

F = 1.52 x 10⁻⁴ N

now calculation of charges

$F = \dfrac{kQ_1Q_2}{r^2}$

Q₁ = Q₂ because both charge are same

$1.52\times 10^{-4} = \dfrac{9\times10^9Q^2}{0.068^2}$

Q² = 7.809 x 10⁻¹⁷

Q = 8.84 x 10⁻⁹ C

hence the change on the balls were Q₁ = Q₂ = 8.84 x 10⁻⁹ C

5 0

4 years ago

The amperage changes on an electrical heater with a rise of temperature because

Nostrana [21]

The electrical free path of electron is disturbed with vibrations not normal to normal / room temperature because the electrical heater is agitating the conductor material. this causes the electrons to vibrate more creating more resistance to the flow.

6 0

3 years ago