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agasfer [191]
3 years ago
15

A coin and feather are dropped in a moon. what will fall earlier on ground.give reasons.if they are dropped in the earth,which o

ne will fall faster?
Physics
1 answer:
Igoryamba3 years ago
8 0

Answer:

When an object is dropped, the "principal" force that acts on that object is the gravitational force.

Thus, in the absence of air resistance and such, the acceleration of the object will be equal to the gravitational acceleration:

g = 9.8m/s^2

So, when we drop objects in the moon (where there is no air) the acceleration of every object will be exactly the same. (so there is no dependence in the mass or shape of the object)

Thus, if we drop a coin and a feather in the moon, both objects will fall with the same acceleration, and then both objects will hit the ground at the same time.

But if we are in Earth, we can not ignore the air resistance (a force that acts in the opposite direction than the movement of the object)

And this force depends on the shape and mass of the object (for example, something with a really larger surface and really thin, like a sheet of paper will be more affected by this force than a small rock)

Then here, when the air resistance applies, we should expect that the heavier and smaller object (the coin) to be less affected by this force, then the resistance that the coin experiences is smaller, then the coin falls "faster" than the feather.

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A student who weighs 500 newtons climbed the stairs from the first floor to the third floor,15 meters above, in 20 seconds. How
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3 years ago
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A circular conducting loop with a radius of 0.10 m and a small gap filled with a 10.0 ȍresistor is oriented in the xy-plane. If
lidiya [134]

Answer:

The magnitude of the current is 5.45 mA.

Explanation:

Given that,

Resistance = 10.0 ohm

Radius = 0.10 m

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Time t = 3.0 s

Number of turns = 1

We need to calculate the initial flux

Using formula of flux

\phi=NB_{1}A\cos\theta

Put the value into the formula

\phi=1\times1.0\times\pi\times(0.10)^2\times\cos30^{\circ}

\phi=1\times1.0\times\pi\times(0.10)^2\times\dfrac{\sqrt{3}}{2}

\phi=0.027\ wb

We need to calculate the final flux

\phi=1\times7.0\times\pi\times(0.10)^2\times\dfrac{\sqrt{3}}{2}

\phi=0.1904\ wb

We need to calculate the induced emf

Using formula of emf

\epsilon=\dfrac{\phi_{f}-\phi_{i}}{t}

Put the value into the formula

\epsilon=\dfrac{0.1904-0.027}{3.0}

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Using formula of current

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3 years ago
A light meterstick is loaded with masses of5.0 kg and 3.0 kg
fredd [130]

Answer:I=3.024\ kg-m^2

Explanation:

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3 years ago
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