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8090 [49]
3 years ago
14

What are some physical properties of a star

Physics
2 answers:
Juli2301 [7.4K]3 years ago
8 0
Distance, how much energy generated in the star, size, temp, brightness
zloy xaker [14]3 years ago
7 0
1. Apparent magnitude
2. Colur Index
3. Annual parallax/variation period if it is Cepheid variable/Red Shift
4. Radial Velocity & Tangential Velocity
Other quantities are derived from the above basic observational data.
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What is the physical representation of the area under a force versus extension or compression curve?
lidiya [134]

The compression curve would be theoretically given for a system of bodies in which the spring applies the force (Although in the same way the following process can be extrapolated to any system, depending on the type of Force to consider) For a spring mass system, the strength is given by Hooke's law as

F = Kx

Where,

K  = Spring constant

x = Displacement

If we integrate based on distance we would have

\int F = \int K x dx

This integral represents the area under the Force Curve based on each distance segment traveled.

\int F = K \int xdx

\int F = K (\frac{1}{2} x^2)

\int F = \frac{1}{2} Kx^2

This is the same formula that represents the elastic potential energy of a body. Therefore the correct answer is D.

5 0
3 years ago
Stems tend to grow in Or against the direction of gravity
Mekhanik [1.2K]
Against due to the fact that they grow up and gravity goes down. 
5 0
3 years ago
You pull a 70-kg crate at an angle of 30° above the horizontal. If you pull with a force of 600N and the coefficient of kinetic
Alenkinab [10]

Answer:

Explanation:

Force of friction acting on the body = μ mg cosθ

= .4  x 70 x 9.8 x cos30

= 237.63 N

component of weight = mgsinθ

= 70 x 9.8 x sin30

= 343 N  

Net upward force = 600 - mgsinθ - μ mg cosθ

= 600 - 343 - 237.63

= 105.37 N

acceleration in upward direction = 105.37 / 70

= 1.5 m /s²

s = ut + 1/2 a t²

= 0 + .5 x 1.5 x 3²

= 6.75 m .

5 0
3 years ago
Astronauts often undergo special training in which they are subjected to extremely high centripetal accelerations. One device ha
egoroff_w [7]

The centripetal acceleration of an object is given by the relation,

Ac =V^2/R

where Ac = centripetal acceleration = 98 m/s^2

R = radius of rotation = 15 m

V = speed of astronaut

Hence, \frac{V^2}{15} =98

solving this we get, V = 38.34 m/s

3 0
3 years ago
Read 2 more answers
A 0.280 m radius, 475 turn coil is rotated one-fourth of a revolution in 4.17 ms, originally having its plane perpendicular to a
KonstantinChe [14]
Hope it helps u mate. Plz follow me .

8 0
4 years ago
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