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3 years ago

What are some physical properties of a star

Physics

2 answers:

Juli2301 [7.4K]3 years ago

8 0

Distance, how much energy generated in the star, size, temp, brightness

zloy xaker [14]3 years ago

7 0

1. Apparent magnitude
2. Colur Index
3. Annual parallax/variation period if it is Cepheid variable/Red Shift
4. Radial Velocity & Tangential Velocity
Other quantities are derived from the above basic observational data.

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People have proposed driving motors with the earth's magnetic field. This is possible in principle, but the small field means th

Whitepunk [10]

Answer:

Current needed = 704A

Explanation:

Using the fomula; torque(τ) = (I)(A)(B)Sinθ

Where B = uniform magnetic field

I = current and A = Area

Diameter = 19cm = 0.19m so, radius = 0.19/2 = 0.095m

Area(A) = πr^(2) = πr^(2)

= π(0.095)^(2) = 0.0284 m^(2)

Now, B(earth)= 5x10^-5 T

While, we can ignore the angle because it's insignificant since the angle of the wire is oriented for maximum torque in the earth's field.

Now, if we arrange the formula to solve for charge (I):

I = (τ)/(A)(B)

I = (1.0x10^-3) / (0.0284)(5x10^-5)

I = 704A

6 0

3 years ago

A proton and an electron in a hydrogen atom are separated on the average by about 5.3 × 10−11 m. What is the magnitude and direc

Genrish500 [490]

Answer:

1. 5.12068 × 1011 N/C away from the proton

Explanation:

The electric field produced by a single point charge is given by:

$E=k\frac{q}{r^2}$

where

k is the Coulomb's constant

q is the magnitude of the charge

r is the distance from the charge

In this problem, we have:

$q=1.6\cdot 10^{-19}C$ is the charge of the proton

$r=5.3\cdot 10^{-11} m$ is the distance at which we want to calculate the field

$k=8.99\cdot 10^9 Nm^2C^{-2}$ is the Coulomb's constant

Substituting into the formula,

$E=(8.99\cdot 10^9 Nm^2C^{-2})\frac{1.6\cdot 10^{-19}C}{(5.3\cdot 10^{-11}m)^2}=5.12068\cdot 10^{11} N/C$

And the direction of the electric field produced by a positive charge is away from the charge, so the correct answer is

1. 5.12068 × 1011 N/C away from the proton

4 0

4 years ago

A 16 n force is applied to an object and 96 j of work is done. how far was the object moved?

Natasha2012 [34]

We know, w = F.s

where, s = displacement of object

96 = 16.s

s = 96/16 = 6

Object moved for 6 meters

3 0

3 years ago

Read 2 more answers

Mass is sometimes described as the difficulty of acceleration of an object. How does Newton's second law agree with this descrip

Charra [1.4K]

Answer:

Increasing force tends to increase acceleration while increasing mass tends to decrease acceleration. Thus, the greater force on more massive objects is offset by the inverse influence of greater mass. Subsequently, all objects free fall at the same rate of acceleration, regardless of their mass.

If the mass increases, it's harder to accelerate

6 0

3 years ago

What happens to the coefficient of friction when the weight is increased? Why is this?

Crazy boy [7]

Answer:

Usually the coefficient of friction remains unchanged

Explanation:

The coefficient of friction should in the majority of cases, remain constant no matter what your normal force is. When you apply a greater normal force, the frictional force increases, and your coefficient of friction stays the same. Here's another way to think about it: because the force of friction is equal to the normal force times the coefficient of friction, friction is increased when normal force is increased.

Plus, the coefficient of friction is a property of the materials being "rubbed", and this property usually does not depend on the normal force.

6 0

4 years ago

Read 2 more answers