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Ivenika [448]
3 years ago
10

(x^2+3x-2)dx intergrate

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
4 0

The result follows from the power rule: for <em>n</em> ≠ -1, we have

\displaystyle \int x^n\,\mathrm dx = \dfrac{x^{n+1}}{n+1}+C

So

\displaystyle \int (x^2+3x-2)\,\mathrm dx = \int x^2\,\mathrm dx + 3\int x\,\mathrm dx - 2\int\mathrm dx \\\\ = \boxed{\frac{x^3}3 + \frac{3x^2}2 - 2x + C}

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Answer:

The inches in height will be 18 inches.

Step-by-step explanation:

Okay so we know that the original width is 4 inches and she enlarged that to 12 inches

So what we first have to do is find out how much did the photograph "grow" per se. To find this we have to divide 12 by 4. 12 divided by 4 = 3.

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The inches in height will be 18 inches.

Jill has a square with a width of 12 inches, and a height of 18 inches.

Have a wonderful day!

5 0
3 years ago
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Answer:

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3 years ago
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