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lidiya [134]
3 years ago
8

What is the magnitude of velocity for a 2,000 kg car possessing 3,000 kg(*)m/s of momentum?

Physics
1 answer:
Trava [24]3 years ago
5 0

The magnitude of velocity for this car is equal to 1.5 m/s.

<u>Given the following data:</u>

  • Momentum of car = 3,000 kgm/s.
  • Mass of car = 2,000 kg.

To calculate the magnitude of velocity for this car:

<h3>What is momentum?</h3>

In Science, momentum simply means a multiplication of the mass of an object and its velocity.

Mathematically, momentum is giving by the formula;

Momentum = mass \times velocity

Making velocity the subject of formula, we have:

Velocity=\frac{Momentum}{Mass}

Substituting the given parameters into the formula, we have;

Velocity=\frac{3000}{2000}

Velocity = 1.5 m/s.

Read more on momentum here: brainly.com/question/15517471

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Calculate the rate of energy transfer by a 5 ohms resistor when there is a current of 0.2 A in it.​
vredina [299]

Answer: The rate of energy transfer by a 5 ohms resistor when there is a current of 0.2 A in it.= 1.25 watt.

Explanation:

  • The rate of energy transfer from one point to another is known as power.
  • Its SI. unit is <em>Watt.</em>

Formula to compute power:

Power = I^2 R, I = cureent, R = resistance.

Given R = 5 ohm , Current = 0.5 A.

Then, power = (0.5)^2\times 5=0.25\times5=1.25\ watt

Hence, the rate of energy transfer by a 5 ohms resistor when there is a current of 0.2 A in it.= 1.25 watt.

5 0
3 years ago
PLEASE HELP
Elan Coil [88]

Answer:

Explanation:

a_{x}=0 v_{xo}= v_{o}cos(delta)t a_{y}=-g v_{yo}=sinθ

X-direction                                     | Y-direction

x=x_o+v_{xo}t ⇒ x=v_{xo}cos(delta)t |

5 0
3 years ago
Light enters an equilateral prism with an incident angle of 35° to the normal of the surface. Calculate the angle at which the
julia-pushkina [17]

Answer:

65.9°

Explanation:

When light goes through air to glass

angle of incidence, i = 35°

refractive index, n = 1.5

Let r be the angle of refraction

Use Snell's law

n=\frac{Sini}{Sinr}

1.5=\frac{Sin35}{Sinr}

Sin r = 0.382

r = 22.5°

Now the ray is incident on the glass surface.

A = r + r'

Where, r' be the angle of incidence at other surface

r' = 60° - 22.5° = 37.5°

Now use Snell's law at other surface

\frac{1}{n}=\frac{Sinr'}{Sini'}

Where, i' be the angle at which the light exit from other surface.

\frac{1}{1.5}=\frac{Sin37.5'}{Sini'}

Sin i' = 0.913

i' = 65.9°

4 0
3 years ago
Pls tell the answer asap
Rzqust [24]
The maximum force acts between B and C as the graph is steepest showing maximum deceleration
5 0
3 years ago
A 210 kg meteoroid is heading toward the earth accelerates by 2.4 × 105 m/s2.
Rainbow [258]
According to Newton's second law of motion, Force is the product of mass and acceleration of the object.
So, F = m * a

Here, m = 210 Kg
a = 2.4 * 10⁵ m/s²

Substitute their values, 
F = 210 * 2.4 * 10⁵ N
F = 504 * 10⁵ N
F = 5.04 * 10⁷ N

In short, Your Answer would be Option B

Hope this helps!

6 0
3 years ago
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