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Rufina [12.5K]
2 years ago
9

A 2kg pumpkin is thrown with a velocity of 15m/s towards a

Physics
1 answer:
Lynna [10]2 years ago
7 0

The force exerted on the pumpkin by

the wall is 600N.

HOW TO CALCULATE FORCE:

  • The force exerted by the wall on the pumpkin can be calculated by multiplying the mass of the pumpkin by the acceleration.

  • However, the acceleration of the pumpkin needs to be calculated by the following expression:

  • a = (v - u)/t

Where;

  1. a = acceleration (m/s²)
  2. v = final velocity (15m/s)
  3. u = initial velocity (0m/s)
  4. t = time (0.05s)

  • a = (15 - 0)/0.05

  • a = 15/0.05

  • a = 300m/s²

  • F = 2kg × 300m/s²

  • F = 600N

  • Therefore, the force exerted on the pumpkin by the wall is 600N.

Learn more about force at: brainly.com/question/20207503?referrer=searchResults

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A car is making a 40 mi trip. It travels the first half of the total distance 20.0 mi at 18.00 mph and the last half of the tota
sukhopar [10]

Answer: The average speed is 27,24 mph (exactly 1008/37 mph)

Explanation:

This is solved using a three rule: We know the speeds and the distances, what we can obtain from it is the time used. It is done like this:

1h--->18mi

X ---->20 mi, then X=20mi*1h/18mi= 10/9 h=1,111 h

1h--->56mi

X ---->20 mi, then X=20mi*1h/56mi= 5/14 h=0,35714 h

Then the average speed is calculated by taking into account that it was traveled 40mi and the time used was 185/126 h=1,468 h and since speed is distance over time we get the answer. Average speed= 40mi/(185/126 h)=1008/37 mph=27,24 mph.

5 0
3 years ago
The ice cap at the North Pole may be 1000 m thick, with a density of 920 kg/m3. Find the pressure at the bottom and the correspo
bija089 [108]
<span>Pice=920kg/m^3 deltaP=PgH=920kg/m^3 X 9.80665m/s^2 X 1000m = 9022118 Pa P=Po + deltaP=101.325 + 9022 = 9123kPa</span>
7 0
2 years ago
A 120 kg box is on the verge of slipping down an inclined plane with an angle of inclination of 47º. What is the coefficient of
Alex_Xolod [135]

Given :

A 120 kg box is on the verge of slipping down an inclined plane with an angle of inclination of 47º.

To Find :

The coefficient of static friction between the box and the plane.

Solution :

Vertical component of force :

mg\ sin\ \theta =  120\times 10 \times sin\ 47^\circ{}=877.62 \ N

Horizontal component of force(Normal reaction) :

mg\ cos\ \theta =  120\times 10 \times cos\ 47^\circ{}=818.40 \ N

Since, box is on the verge of slipping :

mg\ sin\ \theta= \mu(mg \ cos\ \theta)\\\\\mu = tan \ \theta\\\\\mu = tan\ 47^o\\\\\mu = 1.07

Therefore, the coefficient of static friction between the box and the plane is 1.07.

Hence, this is the required solution.

7 0
3 years ago
Technician A says that the governor is used to measure vehicle speed in a hydraulically-controlled automatic transmission. Techn
igor_vitrenko [27]

Answer:

Both technicians are correct

Explanation:

In automobiles, governors are being used. Governors are also known for speed limiters as they can regulate and measure the speed of the automobile.

Hydraulic Transmission: Shifting is controlled by mechanical sensors according to vehicle speed and throttle position/manifold vacuum through valving operated by hydraulic 'pilot' signals.

Electronic Transmission: Shifting is controlled by an on-board computer that receives signals from electronic sensors.

3 0
3 years ago
What is the KE if a 10kg mass traveling at 5 m/s
11111nata11111 [884]

Answer: KE = 25 J

Explanation: You must use the formula

KE = 1/2 m v²

to solve this problem.

KE = 1/2 (10 Kg) (5 m/s)

KE = 1/2 (50 kgm/s)

KE = 25 J

7 0
2 years ago
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