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3 years ago

Net force and acceleration

Physics

1 answer:

madreJ [45]3 years ago

6 0

Answer:

net force = 2.4N

a = 6m/s²

Explanation:

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A sound wave of frequency

Artyom0805 [142]

Answer:

0.283m

Explanation:

Speed (v) = wavelength × Frequency (f)

Wavelength = speed/ frequency

Wavelength = 343/ 1210 = 0.283m

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3 years ago

Why are movie scenes in outer space often unrealistic?

kifflom [539]

Answer:

see explanation

Explanation:

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2 years ago

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Two horses on opposite sides of a narrow stream are pulling a barge up the stream. Each hors pulls with a force of 720N. The rop

Sonja [21]

For the answer to the question above, each horse's force forms a right angle triangle with the barge and subtends an angle of 60/2 = 30°. The resultant in the direction of the barge's motion is:
Fx = Fcos(∅)
We can multiply this by 2 to find the resultant of both horses.
Fx = 2Fcos(∅)
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3 years ago

What element is found in liver and is needed to prevent anemia or tired blood

mel-nik [20]

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3 years ago

A person's prescription for her new bifocal glasses calls for a refractive power of -0.450 diopters in the distance-vision part,

Angelina_Jolie [31]

Answer:

Far point of the eye is 22.24 m

Far point of the eye is 0.4 m

Explanation:

$\frac{1}{f}=-0.045$

Object distance = u

Image distance = v

Lens equation

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=-0.045-\frac{1}{\infty}\\\Rightarrow \frac{1}{v}=\frac{1}{-0.045}\\\Rightarrow v=-22.22\ m$

Far point

$|v|+\text{Position from eye}\\ =|-22.22|+0.02\\ =22.24\ m$

Far point of the eye is 22.24 m

Object distance = u = 0.25-0.02 = 0.23 m

$\frac{1}{f}=1.75$

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=1.75-\frac{1}{0.23}\\\Rightarrow v=-0.38\ m$

Near point

$|v|+\text{Position from eye}\\= |-0.38|+0.02\\ =0.4\ m$

Far point of the eye is 0.4 m

7 0

3 years ago