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2 years ago

7

What is the pathway of sound through fluids starting at the oval window through to dissipation of the sound waves at the round w

indow

1 answer:

ruslelena [56]2 years ago

6 0

Perilymph of scala vestibule; endolymph of cochlear duct; perilymph of scala tympani

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An electric immersion heater is put at the bottom of a large tank of water. The water next to the heater becomes warm

djyliett [7]

Answer:

when the water is heated with immersion heater, the water becomes less dense due to which the warm water rises up and the cooler water fills it's space.

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2 years ago

If you used 16 gallons when driving 367 miles, what was your gas mileage over that distance

White raven [17]

Your gas mileage would be 22.93 miles per gallon.

6 0

2 years ago

The Sun is to a planet as -

serg [7]

Answer:a

Explanation:

5 0

2 years ago

A pin-supported, vertically-oriented 1-m long thin rod is struck by a pellet at m down from the pin at the top. The mass of the

Natasha_Volkova [10]

Answer:

the angular velocity of the rod immediately after being struck by the pellet, provided that the pellet gets lodged in the rod is = 0.5036 k` rad/s

Explanation:

Using the conservation of momentum of approach.

From the question; the pellet is hitting at a distance of 0.4 m down from the point of rotation of the rod.

So, the angular momentum of the system just before the collision occurs with respect to the axis of the rotation is expressed by the formula:

$L_i ^ { ^ \to } = mp ( r_y } ^ { ^ \to } * v_{pi} ^ { ^ \to } )$ ----- equation (1)

The position vector can now be :

$x ^ { ^ \to }$ = $- 0.4 \ j \ m$

Also, given that :

$v_{p,i} ^ { ^ \to } = (280 \ i - 350 \ j) \ m/s$

Replacing the value into above equation (1); we have:

$L_i ^ { ^ \to } =0.012 ((- \ 0.4 \ j) *(280 \ i - 350 \ j ))$

$L_i ^ { ^ \to } =0.012 * 112 \ k$ (by using cross product )

$L_i ^ { ^ \to } = 1.344 k` \ \ kg m^2 s^{-1}$

However; the moment of inertia of the rod about the axis of rotation is :

$I_{rod} = \frac{1}{3}m_rl^2 \\ \\ I_{rod} = \frac{1}{3}*8*1^2 \\ \\ I_{rod} = \frac{8}{3} \ \ kg \ m^2$

Also, the moment of inertia of the pellet about the axis of rotation is:

$I_{pellet} = m_pr_y^2 \\ \\ I_{pellet} = 0.012 *0.4^2 \\ \\ I_{pellet} = 1.92*10^{-3} kg . m^2$

So, the moment of inertia of the rod +pellet system is:

$I = I_{rod}+I_{pellet}$

$I =( \frac{8}{3}+1.92 *10^{-3} )kg. m^2$

$I = 2.6686 \ kg. m^2$

The final angular momentum is :

$L_f ^ {^ \to} = I \omega { ^ {^ \to} } = 2.6686 \ \omega ^ {^ \to}$

The angular velocity of the rod $\omega$ is determined by equating the angular momentum just before the collision with the final angular momentum (i.e after the collision).

So;

$L_f ^ {^ \to} = L_i ^ { ^ \to}$

$2.6686 \omega ^ {^ \to} = 1.344 \ k ^ {^ \to}$

$\omega ^ {^ \to} = \frac{1.344 \ k`}{2.6686}$

= 0.5036 k` rad/s

Hence; the angular velocity of the rod immediately after being struck by the pellet, provided that the pellet gets lodged in the rod is = 0.5036 k` rad/s

7 0

2 years ago

Where were most of the elements "forged" on the periodic table

klemol [59]

<h2>Answer: Stars</h2>

Most of the chemical elements of the Periodic Table were formed or "<em>forged</em>" in the different types of stars that exists in the universe in their different phases of life.

For example, a young star is composed mainly of Hydrogen, the simplest chemical substance and <u>the first in the Periodic Table</u>; being this the element that leads to the other known elements. Taking into account that the two components of each hydrogen atom (1 proton and 1 electron) are separated, the great pressure within the star manages to merge (fuse) two protons.

What does this mean?

Well, sometimes a proton captures an electron and becomes a neutron, but when two protons and two neutrons join together, they form the Helium nucleus, which is <u>the second element in the periodic table</u>. Then, when two helium nuclei join and form the nucleus of another element, Beryllium and so on.

So, by means of the nuclear fusion process the nuclei of most of the elements lighter than Iron (which is the chemical element 26 of the periodic table) can be formed.

Now, elements that are heavier than Iron can be forged within the stars through the capture of neutrons. In this way, the collapse of the star's center core occurs so quickly that it generates huge shock waves that eject the outer layers of the star into space becoming a <u>supernova</u>. Then, it is during the few seconds of collapse that the specific pressure and temperature conditions in the supernova are created and allow heavier elements to be generated and expelled as interstellar dust and gas.

In this sense, with the explosion of more<u> massive stars</u> and <u>white dwarfs</u> other chemical elements are formed, as well as others that are formed by <u>dying stars of low mass</u> and <u>neutron stars</u>.

However, it should be noted that there are also chemical elements that are artificially formed in experimental fusion nuclear reactors.

4 0

2 years ago