All categories

3 years ago

If you continue operating the tractor at its current level, how many acres can you expect to fertilize in the next hour?

Biology

1 answer:

marta [7]3 years ago

5 0

Answer:

200 acres because you have on tractor going 20 in 4hours you multiply by five giving you 100 and then times 2 because the hours are doubled

Explanation:

Hope this helps:)

You might be interested in

A spheroidal bacterium with a diameter of 1 mm contains 2 molecules of a particular protein. What is the molar concentration?

creativ13 [48]

Answer : The molar concentration is, $6.35\times 10^{-18}mol/L$

Explanation :

First we have to calculate the moles of protein.

$\text{Moles of protein}=\frac{\text{Number of molecules of protein}}{\text{Avogadro's number}}$

Number of molecules of protein = 2 molecules

Avogadro's number = $6.022\times 10^{23}molecules/mol$

$\text{Moles of protein}=\frac{2\text{ molecules}}{6.022\times 10^{23}molecules/mol}=3.32\times 10^{-24}mol$

Now we have to calculate the radius.

Radius = $\frac{Diameter}{2}=\frac{1mm}{2}=0.5mm=5.0\times 10^{-4}m$

Conversion used : (1 mm = 0.001 m)

Now we have to calculate the volume.

$V=\frac{4}{3}\pi r^3$

$V=\frac{4}{3}\times 3.14\times (5.0\times 10^{-4}m)^3$

$V=5.23\times 10^{-10}m^3=5.23\times 10^{-7}L$

Conversion used : (1 m³ = 1000 L)

Now we have to calculate the molar concentration.

$Concentration=\frac{\text{Moles of protein}}{\text{Volume}}$

$Concentration=\frac{3.32\times 10^{-24}mol}{5.23\times 10^{-7}L}$

$Concentration=6.35\times 10^{-18}mol/L$

Thus, the molar concentration is, $6.35\times 10^{-18}mol/L$

4 0

3 years ago

Which molecules do cells need to release energy? Choose the claim you think is most accurate. Claim 1: Cells need glucose to rel

Paraphin [41]

Answer:

i don’t know if it’s a multi question but here are my answer bellow

Claim 1:Cells need glucose to release energy

Claim 3:Cells need oxygen to release energy.

Claim 5:Cells need glucose AND oxygen to release energy

4 0

2 years ago

How would an inhibitor of cAMP phosphodiesterase affect glucose mobilization in muscle? It would increase cAMP levels, which wou

dedylja [7]

Answer:It would maintain high cAMP levels and elevate glucose mobilization.

Explanation:

Gas stimulates adenylate cyclase, leading to the generation

of cAMP. This signal then leads to glucose mobilization. If cAMP phosphodiesterase were inhibited, then

cAMP levels would remain high even after the termination of the

epinephrine signal, and glucose mobilization would continue

5 0

3 years ago

Pain signals often have two components: an acute sensation of "first pain" which is felt almost immediately after an injury, and

o-na [289]

Answer:

This suggests that neurons that send the signals that we perceive as first pain Myelinated Tpye A-delta___, and neurons that send the signals that we perceive as second pain Unmyelinated-Type C.___.

Explanation:

Physiologically, primary afferent neurons that innervated the the touch, pain, temperature,and pressure receptors in the effectors to input sensory signals to the spinal cord and the brain are categorized based on their diameter, sizes, and nature of myelination. Based on this;

A-alpha has the largest diameter, myelinated, and sensitive to sensation from the muscle cells

A-beta are next in diameter, myelinated and sensitive to sensation of touch.

A-delta followed in diameter, and size. They are mylinated, and sensitive to pain and temperature.

C-fibres are least in diameter, they are unmyelinated, but sensitive to pain, touch and temperature.

Therefore, if the speed of conduction,of action potential in a neuron depends on the diameter(thickness) and myelination of the axon(saltatory conduction) :

''then, acute sensation/ first pain should be transmitted by the A-delta fibre. While the the slower/second pain should be transmitted by the slower unmyelinated - C-fibres''.

5 0

3 years ago

Juan received a class assignment to write about organisms that live in extreme environments. While doing research online, he fou

earnstyle [38]

Answer:

D. archea

Explanation:

8 0

1 year ago