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3 years ago

8

Can someone help me solve this question? Step by step please

1 answer:

Nina [5.8K]3 years ago

8 0

So what we do is we first get the x on the right side: 7x-x = 6x.

Now we get the 5 to the left side: 71-5= 66.

Now our equation is 66=6x.
We divide 66 by 6 which makes x=11

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You roll a number cube twice. Find the probability of the events. Rolling an even number of 5.

lys-0071 [83]

Answer:

An even number and a 5. In the first roll you can get 2, 4 or 6, so you have 3 out of 6 options, the probability is 3/6 = 1/2, in the second roll you need you get a 5, the probability is 1/6.

I really hope this helps please give brainliest!!!!

5 0

3 years ago

Nineteen students were invited to michelle's party. Three more boys than girls were invited. How many boys were invited?

bekas [8.4K]

11 boys and 8 girls because you divide it in half the add 2 and subtract 1. That isn't the wy you are supposed to do it but it works and makes since in my head.

7 0

3 years ago

Read 2 more answers

Prove that is here<br><img src="https://tex.z-dn.net/?f=1%20-%20cos%20%7B2%7Da%20%5Cdiv%201%20-%20sin%20a%7B2%7D%20%20%3D%20tan%

garri49 [273]

$\\ \sf\longmapsto \dfrac{1-cos2A}{1-sin2A}$

<h3>LHS</h3>

$\boxed{\sf \dfrac{cosA}{sinA}=cotA}$

$\\ \sf\longmapsto \dfrac{1-cos2A}{1-sin2A}$

$\\ \sf\longmapsto 1-cot2A$

$\\ \sf\longmapsto 1-\dfrac{1}{tan2A}$

$\\ \sf\longmapsto \dfrac{tan2A-1}{tan2A}$

$\\ \sf\longmapsto tan2A$

8 0

3 years ago

How to do this please and what's the answer

nalin [4]

This is how you do it! Please let me know if you need help.

5 0

3 years ago

SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP

nata0808 [166]

Answer:

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$x=-4,\:y=3$

Step-by-step explanation:

Given the system of the equations

$x+3y=5;\:x=-6y+14$

solving by elimination method

$\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}$

$\mathrm{Arrange\:equation\:variables\:for\:elimination}$

$\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}$

$x+6y=14$

$-$

$\underline{x+3y=5}$

$3y=9$

$\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}$

solve $3y=9$ for $y$ :

$3y=9$

$\frac{3y}{3}=\frac{9}{3}$

$y=3$

$\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3$

Solve $x+3\cdot \:3=5$ for x:

$x+3\cdot \:3=5$

$x+9=5$

$x=-4$

Therefore,

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$x=-4,\:y=3$

6 0

3 years ago