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dalvyx [7]
3 years ago
8

Can someone help me solve this question? Step by step please

Mathematics
1 answer:
Nina [5.8K]3 years ago
8 0
So what we do is we first get the x on the right side: 7x-x = 6x.

Now we get the 5 to the left side: 71-5= 66.

Now our equation is 66=6x.
We divide 66 by 6 which makes x=11
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10 more than a number w is -2.6
OLEGan [10]
What kind of question is that? That’s a statement.
6 0
3 years ago
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A number cube with six sides numbered 1 through 6 is rolled. the probability of rolling a 5 is 16 . what is the probability of n
egoroff_w [7]
1/6 hope this helps you give a brainliest please thank you.
6 0
3 years ago
X/2 - y/3 = 3/2<br>X/3 + y/2 = 16/3
Ivenika [448]
X/2-y/3=3/2
(6×x/2)-(6×y/3)=6×3/2
3x-2y=9______(1)

x/3+y/2=16/3
(6×x/3)+(6×y/2)=6×16/3
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4 0
3 years ago
Simplify the expression 14b-2-17b
Kamila [148]
The answer to the following question that you have asked is -2-3b
4 0
3 years ago
What is the probability of rolling a sum of 3 on a standard pair of six-sided dice?
salantis [7]

To solve this problem, let us recall that the formula for probability is:

Probability = total number of successful events / total events

 

Where in this case, an event is considered to be successful if the sum is 3 on the pair of six sided dice.

 

First, let us calculate for the total number of events. There are 6 numbers per dice, therefore the total number of combinations is:

total events = 6 * 6 = 36

 

Next, we calculate for the total number of combinations that result in a sum of 3. We can identify that there are only two cases that result in sum of 3. That is:

1st case: first dice rolls 1, second dice rolls 2

2nd case: first dice rolls 2, second dice rolls 1

 

Hence, total number of successful events = 2. Therefore the probability is:

Probability = 2 / 36 = 1 / 18 = 0.0556 = 5.56%

5 0
3 years ago
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