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2 years ago

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Determine whether the lines l1 and l2 given by the vector equations are parallel, perpendicular, or neither. L1: r(t) = (-4 + 3t

)i + (5 + t)j l2: r(s) = (5 + 2s)i + (1 - 6s)j

1 answer:

Vilka [71]2 years ago

4 0

Over which interval(s) is the function decreasing?

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X^2=-144 <br><br> Solve by factoring

Sindrei [870]

Answer: it would be 12

Step-by-step explanation: because if you times 12 twice you would get 144

6 0

2 years ago

A rectangle has a length that is 8 less than its width, w. The perimeter is 52. Which equation can be used to determine its

Juliette [100K]

Answer:

2(w-8) +2w=52

its perimeter so u multiply everything by 2 and since u dont know the length but know its 8 less u subtract by width

7 0

2 years ago

Read 2 more answers

The square of a negative number is twenty-eight more than three times the negative number. Find the number.

MAXImum [283]

The number is x

it is negative
the square is 28 more than 3 times itself
x²=28+3x
minus (28+3x)
x²-3x-28=0
factor
(x-7)(x+4)=0
set to zero

x-7=0
x=7
this is not the answer because we were told the number was negative

x+4=0
x=-4
correct

the number is -4
test
(-4)²=28+3(-4)
16=28-12
16=16
check

the number is -4

8 0

2 years ago

Read 2 more answers

{2x + 3y = 5}{ y= 5 x -4}

Natasha_Volkova [10]

Solve the system using substitutions:

$\begin{gathered} 2x+3y=5 \\ 2x+3(5x-4)=5 \\ 2x+15x-12=5 \\ 17x=5+12 \\ 17x=17 \\ x=\frac{17}{17} \\ x=1 \end{gathered}$

x has a value of 1. Use this value to find the value of y.

$\begin{gathered} y=5x-4 \\ y=5\cdot1-4 \\ y=5-4 \\ y=1 \end{gathered}$

y has a value of 1.

x=1

y=1

8 0

1 year ago

A Web music store offers two versions of a popular song. The size of the standard version is 2.8 megabytes (MB). The size of the

Serga [27]

Answer:

Number of high quality version downloads = 880

Step-by-step explanation:

Let,

x be the number of standard version songs downloaded

y be the number of high quality version songs downloaded

According to given statement,

x+y=1600 Eqn 1

2.8x+4.1y=5624 Eqn 2

Multiplying Eqn 1 by 2.8 to eliminate x

2.8(x+y=1600)

2.8x+2.8y=4480 Eqn 3

Subtracting Eqn 3 from Eqn 2

(2.8x+4.1y)-(2.8x+2.8y)=5624-4480

2.8x+4.1y-2.8x-2.8y=1144

1.3y=1144

Dividing both sides by 1.3

$\frac{1.3y}{1.3}=\frac{1144}{1.3}\\y=880$

Hence,

Number of high quality version downloads = 880

3 0

3 years ago