we know that
The probability that "at least one" is the probability of exactly one, exactly 2, exactly 3, 4 and 5 contain salmonella.
The easiest way to solve this is to recognise that "at least one" is ALL 100% of the possibilities EXCEPT that none have salmonella.
If the probability that any one egg has 1/6 chance of salmonella
then
the probability that any one egg will not have salmonella = 5/6.
Therefore
for all 5 to not have salmonella
= (5/6)^5 = 3125 / 7776
= 0.401877 = 0.40 to 2 decimal places
REMEMBER this is the probability that NONE have salmonella
Therefore
the probability that at least one does = 1 - 0.40
= 0.60
the answer is
0.60 or 60%
Answer:
Step-by-step explanation:
Answer:
11. 736080 cars // 12. 5397920 cars
Step-by-step explanation:
given total number of cars produced : 6,134,000
100% -->6,134,000
1%--> 6,134,000 /100
1% --> 61340
given big cars of America is 12%
so to find this 12% = 12 * 61340 = 736080 cars produced by America
by other manufactures = total cars - big cars of America
= 6,134,000 - 7,36,080
= 5397920 cars
BE is parallel to CD, therefore, m∠BEC=m∠ECD, therefore mBC=mDE
BE is the diameter, so Arc BE is 180 degree
mBC+mCD+mDE=180
replace mCD with 3mBC, and replace mDE with mBC: mBC+3mBC+mBC=180
5mBC=180
mBC=180/5=36
mCD=3mBC=3*36=108
the inscirbed angle m∠ECD= the measure of arc DE=36
(x,y)
y=mx+b
m=slope
b=yintercept
slope=7/10
one point is (1,2) or x=1, then y=2
find b
y=7/10x+b
2=7/10(1)+b
2=7/10+b
minus 7/10 both sides
1 and 3/10=b
13/10=b
y=7/10x+13/10
input values for x and get values for y
one point is (0,13/10)