Answer:
12. 1 second, 35 ft; 2 seconds, 32 ft
13. (t, y) = (1.4 seconds, 37.6 feet)
14. 37.6 ft; the vertex is the highest point
Step-by-step explanation:
12. You have properly answered question 12.
After 1 second, the height is 35 feet; after 2 seconds, it is 32 feet.
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13. My method of choice is to plot the graph on a graphing calculator and let it show me the coordinates of the vertex when I highlight that point. (See attached.) The vertex is ...
(t, y) = (1.4, 37.6)
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14. The graph is a graph of height when the object is launched with a vertical velocity of 45 ft/s. So, the maximum of the graph will correspond to the maximum height of the object. The vertex is that maximum point, and its y-coordinate is that maximum height.
The maximum height is 37.6 feet.
x2=36
We move all terms to the left:
x2-(36)=0
We add all the numbers together, and all the variables
x^2-36=0
a = 1; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·1·(-36)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
x1=−b−Δ√2ax2=−b+Δ√2a
Δ‾‾√=144‾‾‾‾√=12
x1=−b−Δ√2a=−(0)−122∗1=−122=−6
x2=−b+Δ√2a=−(0)+122∗1=122=6
1,2,4,8 I might of missed something
Answer:
Thx for the points
Step-by-step explanation: