Answers and Step-by-step explanations:
When rounding, you should always look at the placement behind what you are trying to round to. So instead of looking at the hundred's placement, which is 0, we need to look at the ten's placement.
(Important:) When rounding, you should always remember that if a number is 1 - 4 when rounding, it does not round up the the next placement. If a number is 5 - 9, then it gets rounded to the next placement.
<em>Hundred's placement:</em> The 9 in the <u>ten's spot </u>(5,0<u>[9]</u>9.620) is on the 5 - 9 scale, so the hundred's placement rounds up to the next number.
5,100.620
<em>Hundredth's placement:</em> Anytime that the "th" is at the end of a word like "hundred" in rounding, it means to go behind (or to the right of) the decimal point. So, 2 falls into the 1 - 4 scale, so it doesn't get rounded.
5,099.600 (or 5,100.600 because of the answer earlier.)
I hope this helps.
For question 4 it will be 416.666666667 so to make it easier you can just put "They have to provide about 416.67 pound of food each day"
Cause god made it that way lol
Answer:
The new mean is 5.
The new standard deviation is also 2.
Step-by-step explanation:
Let the sample space of hours be as follows, S = {x₁, x₂, x₃...xₙ}
The mean of this sample is 4. That is,![\bar x=\frac{x_{1}+x_{2}+x_{3}+...+x_{n}}{n}=4](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7Bx_%7B1%7D%2Bx_%7B2%7D%2Bx_%7B3%7D%2B...%2Bx_%7Bn%7D%7D%7Bn%7D%3D4)
The standard deviation of this sample is 2. That is,
.
Now it is stated that each of the sample values was increased by 1 hour.
The new sample is: S = {x₁ + 1, x₂ + 1, x₃ + 1...xₙ + 1}
Compute the mean of this sample as follows:
![\bar x_{N}=\frac{x_{1}+1+x_{2}+1+x_{3}+1+...+x_{n}+1}{n}\\=\frac{(x_{1}+x_{2}+x_{3}+...+x_{n})}{n}+\frac{(1+1+1+...n\ times)}{n}\\=\bar x+1\\=4+1\\=5](https://tex.z-dn.net/?f=%5Cbar%20x_%7BN%7D%3D%5Cfrac%7Bx_%7B1%7D%2B1%2Bx_%7B2%7D%2B1%2Bx_%7B3%7D%2B1%2B...%2Bx_%7Bn%7D%2B1%7D%7Bn%7D%5C%5C%3D%5Cfrac%7B%28x_%7B1%7D%2Bx_%7B2%7D%2Bx_%7B3%7D%2B...%2Bx_%7Bn%7D%29%7D%7Bn%7D%2B%5Cfrac%7B%281%2B1%2B1%2B...n%5C%20times%29%7D%7Bn%7D%5C%5C%3D%5Cbar%20x%2B1%5C%5C%3D4%2B1%5C%5C%3D5)
The new mean is 5.
Compute the standard deviation of this sample as follows:
![s_{N}=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}\\=\frac{1}{n-1}\sum ((x_{i}+1)-(\bar x+1))^{2}\\=\frac{1}{n-1}\sum (x_{i}+1-\bar x-1)^{2}\\=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}\\=s](https://tex.z-dn.net/?f=s_%7BN%7D%3D%5Cfrac%7B1%7D%7Bn-1%7D%5Csum%20%28x_%7Bi%7D-%5Cbar%20x%29%5E%7B2%7D%5C%5C%3D%5Cfrac%7B1%7D%7Bn-1%7D%5Csum%20%28%28x_%7Bi%7D%2B1%29-%28%5Cbar%20x%2B1%29%29%5E%7B2%7D%5C%5C%3D%5Cfrac%7B1%7D%7Bn-1%7D%5Csum%20%28x_%7Bi%7D%2B1-%5Cbar%20x-1%29%5E%7B2%7D%5C%5C%3D%5Cfrac%7B1%7D%7Bn-1%7D%5Csum%20%28x_%7Bi%7D-%5Cbar%20x%29%5E%7B2%7D%5C%5C%3Ds)
The new standard deviation is also 2.
Answer:
8300
Step-by-step explanation:
First, do parenthesis
Then, do the rest of the PEMDAS
Last, you're done!