All categories

3 years ago

PLEASE HELP ME WITH THIS

Mathematics

1 answer:

noname [10]3 years ago

4 0

Volume of rectangular prism

V = Bh

V = 5/24 cubic units and B = 1/5 square units

h = V/B

h = 5/24 / (1/5)

h = 5/24 x 5/1

v = 1/24

answer is A. 1/24 unit

You might be interested in

Please helppp!!!!!!! And please show your work so i can know what to do next time i have this same problem !

solmaris [256]

Answer: The answer is $152.25

Step-by-step explanation:

First you multiply 0.07 by 163.71 to get 11.4597.

The you subtract 163.71 from 11.4597.

Then that's your answer. I hope this helped!

4 0

2 years ago

What is 4664 ➗ by 94

PilotLPTM [1.2K]

49.617 ( alternative form )

6 0

3 years ago

Find the missing dimension. Use the scale factor 1 : 12. <br> x is 21 cm

Rudik [331]

Answer:

x=7/4

Step-by-step explanation:

Tell me if you need an explanation

8 0

3 years ago

Read 2 more answers

If f(x) = x-6 and g(x)= 1/2x (x+3), find g(x) * f(x)

sertanlavr [38]

Answer:

Final answer is $g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}$ .

Step-by-step explanation:

given functions are $f(x)=x-6$ and $g\left(x\right)=\frac{1}{2x\left(x+3\right)}$ .

Now we need to find about what is the value of $g\left(x\right)*f\left(x\right)$ .

$g\left(x\right)*f\left(x\right)$ simply means we need to multiply the value of $f(x)=x-6$ and $g\left(x\right)=\frac{1}{2x\left(x+3\right)}$ .

$g\left(x\right)\cdot f\left(x\right)=\frac{1}{2x\left(x+3\right)}\cdot\left(x-6\right)$

$g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}$

Hence final answer is $g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}$ .

5 0

2 years ago

The half-life of Radium-226 is 1590 years. If a sample contains 200 mg, how many mg will remain after 1000 years?

adell [148]

Answer: 129.33 g

Step-by-step explanation:

$$$Let $p=A \cdot e^{n t}$ \\$(p=$ present amount, $A=$ initial amount, $n=$ decay rate, $t=$ time)$

$\begin{aligned}&\Rightarrow \text { Given } p=\frac{A}{2} \ a t \ t=1590 \\&\Rightarrow \frac{1}{2}=e^{1590n} \Rightarrow n=\frac{\ln (1 / 2)}{1590}=-0.00043594162\end{aligned}$

$If $A=200 \mathrm{mg}$ and $t=1000$ then,$$\begin{aligned}P &=200 e^{\left(\frac{\ln \left(1/2\right)}{1590}\right) \cdot 1000} \text \\\\&=129.33 \text { grams}\end{aligned}$

3 0

2 years ago