Answer: 30
Step-by-step explanation:
Let the number be y
Add 5 to me
Y+5............equ1
Divide by 7
Y+5/7
Add 12
Y+5/7+12
Subtract 7
(Y+5)/7+(12-7)=10
12-7=5
Substitute
(Y+5)/7+5=10
Find the lowest common multiple
((Y+5)+7(5))/7=10
(Y+5)+35)/7=10
Cross multiply
Y+5+35=70
Y+40=70
Y=70-40
Y=30
The unknown number is 30
Answer:
B
Step-by-step explanation:
Answer:
= 30,550 rupee owed
Step-by-step explanation:
yr1 = 50000 x 0.10^1 = 5000
5000 - 10000 = 5000 credit from debt.
yr 2 = 50000 x 1.10^2 = 500 debit from debt = 5000-15000= 10,000 credit from debt
yr 3 = 50000 x 1.10^3 = 50 debit from debt
5000 + 500 = 15000 where 50,000 owed initially and yr1 and yr 2 paid in full interest of 5500 and we deduct this from his payment = 25000-5500 =
19500 paid of initial and nothing owed on interest.
50000-19500= 30,500 rupees owed + 50 rupee interest.
= 30,550 rupee owed
Let's find out the gradient (Slope " m ") of line q ;
Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :
Now, plug in the value of gradient ~
here we can clearly observe that, the Area under the curve can easily be represented as :
Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q
