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scZoUnD [109]
3 years ago
14

Given a graph for the transformation of f(x) in the format g(x) = f(x) + k, determine the k value.

Mathematics
1 answer:
enyata [817]3 years ago
3 0

Answer:

k=6

Step-by-step explanation:

The parabola that opens up and passes through (-3,-3) will have equation,

f(x) =  {x}^{2}  - 12

The parabola the opens up a d passes through (-3,3) will have equation:

g(x) =  {x}^{2}  - 6

We want to determine the value of k, for which,

g(x) = f(x) + k

We rewrite g(x) in terms of f(x) to get:

{x}^{2}  - 6 =  {x}^{2}   - 12 + 6

g(x)  \to({x}^{2}  - 6 )= f(x) \to ({x}^{2}   - 12 )+k  \to6

Therefore;

g(x) = f(x) + 6

Hence k=6

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First make it that both denominators are the same.
(\frac{1}{2}  \times 5) + ( \frac{2}{5} \times 2) =  \frac{5}{10}  +  \frac{4}{10}
Then add both numerators
\frac{5}{10}  +  \frac{4}{10}  =  \frac{9}{10}
Your final answer should be
\frac{9}{10}
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Answer:

x ≈ 1.4

Step-by-step explanation:

Using the sine ratio in the right triangle

sin50° = \frac{opposite}{hypotenuse} = \frac{RS}{RT} = \frac{x}{1.8} ( multiply both sides by 1.8 )

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Domain and, range in interval notation
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Range: [-4,4] (down-to-up or y-values used)

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2 years ago
A car has mass 1500 kg and is traveling at a speed of 35 miles/hour. what is its kinetic energy in joules? (Be sure to convert m
photoshop1234 [79]

Answer:

Factor by which kinetic energy increase = 4 times

Step-by-step explanation:

Given,

  • Mass of the car, v1 = 1500 kg
  • initial speed of car = 35 miles/h

                               =\dfrac{35\times 1609.34}{3600}\ m/s

                               = 15.64 m/s

Initial kinetic energy of the car is given by,

k_1\ =\ \dfrac{1}{2}.m.v_1^2

       =\ \dfrac{1}{2}\times 1500\times (15.64)^2\ joule

       = 183606.46 J

  • Final velocity of car v2 = 70 miles/hour

                                      =\dfrac{70\times 1609.34}{3600}

                                      = 31.29 m/s

So, final kinetic energy of car is given by

k_2\ =\ \dfrac{1}{2}.m.v_2^2

        =\ \dfrac{1}{2}\times 1500\times (31.29)^2

        = 734425.84 J

Now, the ratio of final to initial kinetic energy can be given by,

\dfrac{k_2}{k_1}=\ \dfrac{734425.84}{183606.46}

=>\ k_2\ =\ 4k_1                      

Hence, the kinetic energy will increase by 4 times.

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Which graph represents functions f and g?
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The answer is C because it’s the only answer that could be correct.
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