A civil engineer is mapping the overhead clearance of his family's property on a coordinate grid. The ground is represented by t
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Answer: 1.4 seconds
<u>Step-by-step explanation:</u>
The equation is: h(t) = at² + v₀t + h₀ where
- a is the acceleration (in this case it is gravity)
- v₀ is the initial velocity
- h₀ is the initial height
Given:
- a = -9.81 (if it wasn't given in your textbook, you can look it up)
- v₀ = 12
- h₀ = 3
Since we are trying to find out when it lands on the ground, h(t) = 0
EQUATION: 0 = 9.81t² + 12t + 3
Use the quadratic equation to find the x-intercepts
a=-9.81, b=12, c=3
Note: Negative time (-0.2) is not valid
Answer:
144°
Step-by-step explanation:
First, find the area of the circle, with the formula A = r²
Plug in 10 as the radius, and solve
A = r²
A = (10²)
A = 100
Using this, create a proportion that relates the area of the sector to the degree measure of the arc.
Let x represent the degree measure of the arc of the sector:
=
Cross multiply and solve for x:
100x = 14400
x = 144
So, the degree measure of the sector arc is 144°