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2 years ago

What is the area of this parallelogram?

Mathematics

2 answers:

Katarina [22]2 years ago

8 0

Answer:

Step-by-step explanation:

Area of a parallelogram

is bxh

alisha [4.7K]2 years ago

5 0

Answer:

Step-by-step explanation:

the base is 10 the height is 3

10 x 3 = 30

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Finding the perimeter of each rectangle 96ft width 124ft length

dezoksy [38]

Answer:

440 ft

Step-by-step explanation:

Perimeter(p) of a rectangle is 2l + 2w

Where 'l' is the length and 'w' is the width.

p = 2(96ft) + 2(124ft) = 192 ft + 248 ft = 440 ft

5 0

3 years ago

Claire is painting some doors that are all the same size. She used 2 liters of paint to cobe 1 3/5 doors. How many liters of pai

Deffense [45]

Answer:

$1 \dfrac{1}{4} \ liters$

Step-by-step explanation:

Given that:

Claire uses 2 liters of paint to cover 1 3/5 doors

Then in order for her to paint 1 door, She will need:

2 L = 1 3/5 door

x L = 1 door

$x (L) = \dfrac{2 L \times 1 door }{ 1 \dfrac{3}{5} \ door}$

$x (L) = \dfrac{2 L }{ 1 \dfrac{3}{5} }$

$x (L) = \dfrac{2 L }{ \dfrac{8}{5} }$

$x (L) = \dfrac{2 L\times 5 }{ 8 }$

$x (L) = \dfrac{10 \ L }{ 8 }$

$x(L) =1 \dfrac{1}{4} \ L$

4 0

2 years ago

Given that circumference of a circle is 44m. Calculate it's area

dimaraw [331]

Answer:

Area=154.062 $m^{2}$

Step-by-step explanation:

As Circumference of a circle is given by;

$C=2\times \pi\times r$

As the circumference is 44m so we can calculate the value of r by using the above formula.

$44=2\times \pi \times r\\\\\frac{44}{2\pi} =r\\\\\implies r=\frac{22}{\pi} =7.003 m$

Now to Calculate the Area of a Circle.

As the area of a circle is,

$Area =\pi \times r^{2}\\ Area=\pi \times (7.003)^{2} \\Area=\pi \times 49.039\\Area=154.062m^{2}$

3 0

2 years ago

What is the value of x in the diagram below?

elena-14-01-66 [18.8K]

Answer:

Step-by-step explanation:

This is a parallelogram. In parallelogram, opposite sides are equal.

x + 3 = 6

x = 6 - 3

x = 3

4 0

3 years ago

Read 2 more answers

A random variable X with a probability density function () = {^-x > 0

Sliva [168]

The solutions to the questions are

The probability that X is between 2 and 4 is 0.314
The probability that X exceeds 3 is 0.199
The expected value of X is 2
The variance of X is 2

<h3>Find the probability that X is between 2 and 4</h3>

The probability density function is given as:

f(x)= xe^ -x for x>0

The probability is represented as:

$P(x) = \int\limits^a_b {f(x) \, dx$

So, we have:

$P(2 < x < 4) = \int\limits^4_2 {xe^{-x} \, dx$

Using an integral calculator, we have:

$P(2 < x < 4) =-(x + 1)e^{-x} |\limits^4_2$

Expand the expression

$P(2 < x < 4) =-(4 + 1)e^{-4} +(2 + 1)e^{-2}$

Evaluate the expressions

P(2 < x < 4) =-0.092 +0.406

Evaluate the sum

P(2 < x < 4) = 0.314

Hence, the probability that X is between 2 and 4 is 0.314

<h3>Find the probability that the value of X exceeds 3</h3>

This is represented as:

$P(x > 3) = \int\limits^{\infty}_3 {xe^{-x} \, dx$

Using an integral calculator, we have:

$P(x > 3) =-(x + 1)e^{-x} |\limits^{\infty}_3$

Expand the expression

$P(x > 3) =-(\infty + 1)e^{-\infty}+(3+ 1)e^{-3}$

Evaluate the expressions

P(x > 3) =0 + 0.199

Evaluate the sum

P(x > 3) = 0.199

Hence, the probability that X exceeds 3 is 0.199

<h3>Find the expected value of X</h3>

This is calculated as:

$E(x) = \int\limits^a_b {x * f(x) \, dx$

So, we have:

$E(x) = \int\limits^{\infty}_0 {x * xe^{-x} \, dx$

This gives

$E(x) = \int\limits^{\infty}_0 {x^2e^{-x} \, dx$

Using an integral calculator, we have:

$E(x) = -(x^2+2x+2)e^{-x}|\limits^{\infty}_0$

Expand the expression

$E(x) = -(\infty^2+2(\infty)+2)e^{-\infty} +(0^2+2(0)+2)e^{0}$

Evaluate the expressions

E(x) = 0 + 2

Evaluate

E(x) = 2

Hence, the expected value of X is 2

<h3>Find the Variance of X</h3>

This is calculated as:

V(x) = E(x^2) - (E(x))^2

Where:

$E(x^2) = \int\limits^{\infty}_0 {x^2 * xe^{-x} \, dx$

This gives

$E(x^2) = \int\limits^{\infty}_0 {x^3e^{-x} \, dx$

Using an integral calculator, we have:

$E(x^2) = -(x^3+3x^2 +6x+6)e^{-x}|\limits^{\infty}_0$

Expand the expression

$E(x^2) = -((\infty)^3+3(\infty)^2 +6(\infty)+6)e^{-\infty} +((0)^3+3(0)^2 +6(0)+6)e^{0}$

Evaluate the expressions

E(x^2) = -0 + 6

This gives

E(x^2) = 6

Recall that:

V(x) = E(x^2) - (E(x))^2

So, we have:

V(x) = 6 - 2^2

Evaluate

V(x) = 2

Hence, the variance of X is 2

Read more about probability density function at:

brainly.com/question/15318348

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<u>Complete question</u>

A random variable X with a probability density function f(x)= xe^ -x for x>0\\ 0& else

a. Find the probability that X is between 2 and 4

b. Find the probability that the value of X exceeds 3

c. Find the expected value of X

d. Find the Variance of X

7 0

2 years ago