As the frequency of electromagnetic waves increases, what happens to the wavelength
2 answers:
You might be interested in
Answer:
Both rod have the same tensile stress
Explanation:
Given information,
The weight first rod, = 1000 N
The length of first rod, = 2.0 m
The weight second rod, = 500 N
The length of second rod, = 1.0 m
The equation of tensile stress, σ =
where
σ = tensile stress (N/ or Pa)
F = Force (N)
A = Area (N/ or Pa)
so
σ1 = , A = 2πl
=
= N/
now calculate σ2
σ2 =
=
= N/
σ1/σ2 = /
σ1/σ2 = 1
σ1 = σ2
Hence, the tensile stress of first and second rod are the same.
Answer:
The minimum thickness is
Explanation:
generally the equation for thin film interference is mathematically represented as
Where t the thickness
m is any integer
n is the refractive index of the film
is the wavelength of light
Since we are looking for the thickness we make t the subject of the formula
m= 0 cause the thickness is minimum at m=0
Substituting values
The work was done on the gas. and internal energy of the gas will be -13459 J and -21649 J.
<h3>What is work done by gas?</h3>When energy is moved from one store to another, work is completed. Work done on the gas is taken as -ve.
Given data;
Initial pressure(P₁)=1.0 bar
The initial volume, V₁=0.4m³
Final pressure(P₂) =1.4 bar.
work is done on the gas., W=?(-ve)
Heat release= - 8.1 kJ
Change in the internal energy of the gas., ΔE
During the compression process, PV=C
P₁V₁=P₂V₂
1.0 bar × 0.4m³= 1.4 bar ×V₂
V₂=0.285 m³
The work done on the gas will be -13459 J.
The internal energy is found as;
ΔE=q+w
ΔE= -8.1 ×10³ -13549
ΔE=-21649 J
Hence, work was done on the gas. and internal energy of the gas will be -13459 J and -21649 J.
To learn more about the work done by gas refer to;
#SPJ1