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Lisa [10]
3 years ago
8

Two small metallic spheres with equal mass are suspended as pendulums by strings of length L. The sphereshave the same electric

charge and come to equilibrium with each string at an angle of Θ = 10.00° with the vertical. What happens if the electric charges are decreased?
A) Θ decrease

B) Θ increase

C) Θ remains the same

D) distant between spheres increases

Physics
1 answer:
love history [14]3 years ago
3 0

Answer:

<em><u>Two small metallic spheres with equal mass are suspended as pendulums by strings of length L. The sphereshave the same electric charge and come to equilibrium with each string at an angle of Θ = 10.00° with the vertical. What happens if the electric charges are decreased?</u></em><em><u>(</u></em><em><u>D</u></em><em><u>)</u></em>

Explanation:

<em><u>please click the heart and rate excellent and brainleist to </u></em><em><u>❤</u></em><em><u>☺️</u></em><em><u>☻</u></em><em><u>♨️</u></em><em><u>♨️</u></em><em><u>☻</u></em><em><u>☺️</u></em><em><u>❤</u></em>

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ArbitrLikvidat [17]

Answer:

a) The angular acceleration of the beam is 0.5 rad/s²CW (direction clockwise due the tangential acceleration is positive)

b) The acceleration of point A is 3.25 m/s²

The acceleration of point E is 0.75 m/s²

Explanation:

a) The relative acceleration of B with respect to D is equal:

a_{B} =a_{D} +(a_{B/D} )_{n} +(a_{B/D} )_{t}

Where

aB = absolute acceleration of point B = 2.5 j (m/s²)

aD = absolute acceleration of point D = 1.5 j (m/s²)

(aB/D)n = relative acceleration of point B respect to D (normal direction BD) = 0, no angular velocity of the beam

(aB/D)t = relative acceleration of point B respect to D (tangential direction BD)

a_{B} =a_{D}  +(a_{B/D} )_{t}

2.5j=1.5j  +(a_{B/D} )_{t}\\(a_{B/D} )_{t}=j=1m/s^{2}

We have that

(aB/D)t = BDα

Where α = acceleration of the beam

BDα = 1 m/s²

Where

BD = 2

2\alpha =1\\\alpha =0.5rad/s^{2}CW

b) The acceleration of point A is:

a_{A} =a_{D}  +(a_{A/D} )_{t}

(aA/D)t = ADαj

a_{A} =a_{D}  +AD\alpha j\\a_{A}=1.5j+(3.5*0.5)j\\a_{A}=3.25jm/s^{2}

The acceleration of point E is:

(aE/D)t = -EDαj

a_{E} =a_{D}  -ED\alpha j\\a_{E}=1.5j-(1.5*0.5)j\\a_{E}=0.75jm/s^{2}

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sergeinik [125]

C. The Densities are equal.

<h3>What is density?</h3>

Density is mass per unit volume or mass of a unit volume of a material substance.

If m1, V1 and D1 = mass, volume  and density respectively of ball C

m2, V2 and D2 = mass, volume and density respectively of ball D

According to the Question ,

V_{1} = 3V_{2}  , m_{2}  = \frac{1}{3} (m_{1} ) \\ \\= m_{1} = 3m_{2}

Therefore,

\frac{D_{1} }{D_{2} }  = (\frac{m_{1} }{V_{1} } )* (\frac{m_{2} }{V_{2} } )\\ \\= (\frac{3m_{2} }{3V_{2} })*(\frac{V_{2} }{m_{2} }) \\\\= 1

Hence, D1 = D2

Learn more about density here:brainly.com/question/15164682

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