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deff fn [24]
3 years ago
12

Describe a vibration that is not periodic. NO LINKS PLEASE

Physics
1 answer:
Paraphin [41]3 years ago
4 0

Answer:

1)The position change of almost any manually operated room light switch.

2) Sunlight striking a point on the ground on a partly cloudy and windy day

Explanation:

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1<br> Verify the identity. Show your work.<br><br> cot θ ∙ sec θ = csc θ
Fittoniya [83]
To verify the identity, we can make use of the basic trigonometric identities:
cot θ = cos θ / sin θ 
sec θ = 1 / cos <span>θ
csc </span>θ = 1 / sin θ<span>

Using these identities:
</span>cot θ ∙ sec θ = (cos θ / sin θ ) (<span> 1 / cos </span><span>θ)
</span>
We can cancel out cos <span>θ, leaving us with
</span>cot θ ∙ sec θ = 1 / sin θ
cot θ ∙ sec θ = = csc <span>θ</span>
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4 years ago
8 POINTS AND MARK BRAINIEST:
lesya692 [45]

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4 0
3 years ago
When mass m is tied to the bottom of a long, thin wire suspended from the ceiling, the wire's second-harmonic frequency is 180 h
Katena32 [7]
The frequency of the nth-harmonic of a string is given by
f_n =  \frac{n}{2L}  \sqrt{ \frac{T}{\mu} }
where n is the number of the harmonic, L is the length of the string, T the tension and \mu the linear density. 

In our problem, since the mass m is tied to the string, the tension is equal to the weight of the object tied:
T=mg
Substituting into the first formula, we have
f_n =  \frac{n}{2L}  \sqrt{ \frac{mg}{\mu} }

In our problem we have n=2 (second harmonic). In the previous equation, the only factor which is not constant between the first and the second part of the problem is m, the mass. So, we can rewrite everything as
f_2 = K  \sqrt{m}
where we called 
K= \frac{2}{2L}  \sqrt{ \frac{g}{\mu} }

In the first part of the problem, the mass of the object is m and f_2 = 180 Hz. So we can write 
180 Hz = K  \sqrt{m}

When the mass is increased with an additional 1.2 kg, the relationship becomes
270 Hz = K \sqrt{(m+1.2 Kg)}

By writing K in terms of m in the first equation, and subsituting into the second one, we get
180 Hz  \sqrt{ \frac{m+1.2 Kg}{m} }=270 Hz
and solving this, we find
m=0.96 kg


5 0
4 years ago
2. What are the greenhouse gases? Which one is the biggest concern?
nikitadnepr [17]
One example of a greenhouse gas is nuclear power. It gives off heat that is trapped around the earth.
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