The work was done on the gas. and internal energy of the gas will be -13459 J and -21649 J.
<h3>What is work done by gas?</h3>When energy is moved from one store to another, work is completed. Work done on the gas is taken as -ve.
Given data;
Initial pressure(P₁)=1.0 bar
The initial volume, V₁=0.4m³
Final pressure(P₂) =1.4 bar.
work is done on the gas., W=?(-ve)
Heat release= - 8.1 kJ
Change in the internal energy of the gas., ΔE
During the compression process, PV=C
P₁V₁=P₂V₂
1.0 bar × 0.4m³= 1.4 bar ×V₂
V₂=0.285 m³
The work done on the gas will be -13459 J.
The internal energy is found as;
ΔE=q+w
ΔE= -8.1 ×10³ -13549
ΔE=-21649 J
Hence, work was done on the gas. and internal energy of the gas will be -13459 J and -21649 J.
To learn more about the work done by gas refer to;
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Answer:
.09 mm
Explanation:
In case of diffraction by single slit with width a the width of central maxima is given below
width = 2 λD/a
where λ is wavelength of light , D is distance of screen , a is width o slit
substituting the given values
14 x 10⁻³ =
a = .09 mm
b) If a is greater , width of central maxima will be less wide.