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densk [106]
2 years ago
13

Plssss help 20 points plssa If K Mis the perpendicular bisector of JL, find x. Plsss

Mathematics
1 answer:
Viefleur [7K]2 years ago
8 0

Answer:

x= 7

Step-by-step explanation:

4x+9 =11x-61

9 = 7x - 61

70 = 7x

x = 7

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There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl
Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0
3 years ago
3q+4+9=-14 <br> what is Q
BlackZzzverrR [31]

Hi! Your answer is q = -9

Please see an explanation for a better and clear understanding to your problem.

Any questions about my answer and explanation can be asked through comments! :)

Step-by-step explanation:

Since we want to solve for q-term. That means we are going to isolate q-term.

\huge{3q+4+9=-14}

We can add 4 and 9 together.

\huge{3q+13=-14}

Because we want to know the value of q. That means we have to isolate q-term by subtracting both sides by 13.

\huge{3q+13-13=-14-13}\\\huge{3q=-27}

We are reaching to the final step where we divide the whole equation by 3.

\huge{\frac{3q}{3}=-\frac{27}{3}}\\\huge{q=-9}

Finally, the solution for this equation is q = -9. But what if you are not certain or sure about the answer? Let's check it out!

To check the answer, simply substitute q = -9 in the equation.

\huge{3q+4+9=-14}\\\huge{3(-9)+13=-14}\\\huge{-27+13=-14}\\\huge{-14=-14}

Notice that the equation is true for q = -9. Hence, we can conclude that the solution for this equation is q = -9.

Hope this helps!

5 0
3 years ago
Just click the picture you don't have to show your work. IF you want to you can tho.
weeeeeb [17]
The correct answer is A.

That is because the whole paragraph talks about a model car that they are testing but this student is wondering about roller coasters.

Hope this helps :)
8 0
3 years ago
since there are 6 faces on a die there is a 3/6 or 1/2 chance of rolling a die and getting a prime number.
Troyanec [42]
I would say 2/5 chance since 1 is neither prime or composite
8 0
3 years ago
12 days of math challenge​
erastova [34]

Answer:

Reindeer and snowflake are 4

tree is 8

snowman is 1

Step-by-step explanation:

8 0
2 years ago
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