The given above may be modeled by the arithmetic sequence with initial value (I) 2200 and common difference (d) of 70. The number of applicants every year can be written by the equation,
at = a1 + (n - 1) x d
From the given above, n is equal to 4. This corresponds to the term which is 3 years from now.
at = 2200 + (4 - 1) x 70 = 2410
Thus, the enrollment capacity would be 2410 students.
6x - 2 = x + 13
Subtract x
5x - 2 = 13
Add 2
5x = 15, x = 3
Solution: the number is 3
Answer:
22
Step-by-step explanation:
Boys to Girls
5 to 6
10 to ?
Since 10 is twice as much as 5, we have to multiply the number of girls by 2. 6 times 2 is equal to 12. Then, since we need to find the total number of boys and girls, we have to add both sides. 10 (boys) plus 12 (girls) equals 22.
Answer:
3.45
Step-by-step explanation:
That will be 1000 because :explanation