If they fit and have good durability
Friction, engine thrust, normal reaction and weight, these are the forces acting on motor when it moves in a straight line
Answer:
pretty sure its long term but im sorry if im wrong
Explanation:
Answer:
v = 31.3 m / s
Explanation:
The law of the conservation of stable energy that if there are no frictional forces mechanical energy is conserved throughout the point.
Let's look for mechanical energy at two points, the highest where the body is at rest and the lowest where at the bottom of the plane
Highest point
Em₀ = U = m g y
Lowest point
= K = ½ m v²
As there is no friction, mechanical energy is conserved
Em₀ =
m g y = ½ m v²
v = √ 2 g y
Where we can use trigonometry to find and
sin 30 = y / L
y = L sin 30
Let's replace
v = RA (2 g L sin 30)
Let's calculate
v = RA (2 9.8 100.0 sin30)
v = 31.3 m / s
By Newton's Law of Universal Gravitation.
F = GMm/r²
Where F is Force of Gravitation, M = Mass of first object, m = mass of second object, r = distance of separation
From the formula, you can see that if the masses, M and m, increased, the value of F would definitely increase as well.
And if r increased the value of F would be reduced because you would be dividing by a bigger number, but when the value of r is decreased the value of F would be increased, because you would then be dividing by something smaller. Note the r is at the denominator of the formula.
So F would increase if there was increase in Masses and decrease in distance.
So the answer is C. a and b.
