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yuradex [85]
3 years ago
8

We gonna make the girls dance

Physics
1 answer:
Firdavs [7]3 years ago
7 0

Answer:

Definition: poem

Explanation:

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Express the number in scientific notation: 4/100
ankoles [38]

Answer:

4*10^-2

Explanation:

for the scientific notation the first number must be between 1 and 10, so in this case it is 4. 4/100 is also equal to 0.04, and if we could the number of places before 4, there are two, therefore 4 times 10 to the power of -2

5 0
3 years ago
Em um centro de distribuição uma empilhadeira carrega uma caixa de 1000kg até o caminhão responsável pelo transporte desta carga
Yakvenalex [24]

Answer:

F = 592238.09 N

Explanation:

To find the mean force you first calculate the acceleration by using the following kinematic equation:

v^2=v_o^2+2ax\\\\v_o=0m/s\\\\v=10km/h\\\\x=8.4m\\\\

you do "a" the subject of the equation and replace the values of the other parameters:

a=\frac{v^2}{2x}=\frac{10000m/s}{2(8.4m)}=595.23\frac{m}{s^2}

next, the force, by using the second Newton law is:

F=ma=(1000kg)(595.23\frac{m}{s^2})=595238.09\ N

hence, the force is 592238.09 N

- - - - - - - - - - - - - - - - - - - - - - - - - - -

TRANSLATION:

Para encontrar a força média, primeiro calcule a aceleração usando a seguinte equação cinemática:

você faz "a" o assunto da equação e substitui os valores dos outros parâmetros:

Em seguida, a força, usando a segunda lei de Newton, é:

portanto, a força é 592238.09 N

8 0
3 years ago
Before the invention of a wheel turning on an axle, ancient people moved heavy loads by placing rollers under them. (Modern peop
matrenka [14]

Answer:K.E.=36.277+1.0429=37.319 J

Explanation:

Velocity of Top most point of wheel is twice the Velocity of centre of mass of wheel

i.e V_{wheel}=2V_{cm}=0.319 m/s

Thus angular velocity is given by

\omega =\frac{V_{cm}}{R}

\omega =0.465 rad/s

Kinetic\ Energy=Rotational + transtational

K.E.=\frac{1}{2}m_{stone}V^2+2\left [ \frac{1}{2}m_{cyl}\left [ \frac{V}{2}\right ]^2\right ]+2\left [ \frac{1}{2}I\omega ^2\right ]

K.E.=\frac{V^2}{2}\left [ m_{stone}+\frac{m_{roller}}{2}\right ]+I\omega ^2

K.E.=\frac{0.319^2}{2}\left [ 672+\frac{82}{2}\right ]+\frac{82\times 0.343^2\times 0.465^2}{2}

K.E.=36.277+1.0429=37.319 J

3 0
3 years ago
Imagine you are charged to manage a project that aims to install wireless access points (aps) throughout the university campus.
Vitek1552 [10]

If you are charged to manage a project that aims to install wireless access points (aps) throughout the university campus, the steps to a foolproof plan for this project would be -

1. Recognize all of your network’s needs.

The most crucial step in any WiFi installation is probably knowing what your network needs are.

2. Select the appropriate hardware for your wireless network

Finding the ideal access point is much simpler if your needs are clear, but the wide range of options might be difficult.

3. Recognize your devices’ network restrictions.

It’s crucial to keep in mind that other factors besides your Internet connection and network hardware might affect how well your network performs.

4. Take into account the various cables you’ll need to use.

5. Consider how nearby interference may affect the installation of your wireless access point.

6. Decide where to put your wireless access point.

7. Analyze signal strength prior to making a decision.

To know more about access points (aps) visit:

brainly.com/question/14231305

#SPJ4

4 0
1 year ago
WILL GIVE BRAINLIEST
krek1111 [17]

Answer:

I think d

Explanation:

6 0
3 years ago
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