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saveliy_v [14]
3 years ago
15

Select the false statement. Scientific models are:

Physics
2 answers:
Brut [27]3 years ago
5 0

D. Must be implemented using a computer.

It is possible to make scientific models without computers and/or other technology.

ludmilkaskok [199]3 years ago
5 0

Answer:

D.

Explanation:

thnks mark me brainliest

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Nina is working with electricity and shortens the wires through which the current is flowing. What is Nina most likely trying to
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A person walking in high heals can damages the floor by making small dimples in the floor since all their weight is concentrated
iren [92.7K]

Given :

Mass of person, m = 81 kg.

Area of high heal, A = 3.5 cm² = 0.00035 m².

To Find :

The pressure applied by the heal on the ground.

Solution :

We know, pressure is given by :

P = \dfrac{mass}{Area}\\\\P = \dfrac{81}{0.00035} \ N/m^2\\\\P = 231428.57 \ N/m^2

Hence, this is the required solution.

4 0
3 years ago
an athlete runs 5.4 laps around a circular track that is 400.0 m long. If this takes 540 s, what is the average velocity of the
Slav-nsk [51]

Answer:

Average velocity is 0.296 m/s.

Average speed is 4.0  m/s.

Explanation:

Given:

Distance of the circular track is, D=400.0\ m

Number of laps ran is, n=5.4

Time taken for the run is, t=540\ s

Now, total distance covered in 5.4 laps = D_T=D\times n=400\times 5.4=2160\ m

Also, since the path is a circle, the final position of the athlete after 5.4 laps will be 0.4 of 400 m ahead of the starting point.

Distance covered in 0.4 laps is, \textrm{Displacemet}=0.4\times 400=160\ m

Therefore, the displacement of the athlete will be 160 m as the athlete is 160 m ahead of the starting point and displacement depends on the initial and final points only.

Now, average velocity is given as:

v_{avg}=\frac{\textrm{Displacemet}}{t}=\frac{160}{540}=0.296\ m/s

Average speed is the ratio of total distance covered to total time taken.

So, average speed = \frac{D_T}{t}=\frac{2160}{540}=4\ m/s

6 0
4 years ago
15) A 328-kg car moving at 19.1 m/s in the +x direction hits from behind a second car moving at 13 m/s in the same direction. If
kolbaska11 [484]

Answer:

Explanation:

Given that,

Mass of first car

M1= 328kg

The car is moving in positive direction of x axis with velocity

U1 = 19.1m/s

Velocity of second car

U2 = 13m/s, in the same direction as the first car..

Mass of second car

M2 = 790kg

Velocity of second car after collision

V2 = 15.1 m/s

Velocity of first car after collision

V1 =?

This is an elastic collision,

And using the conservation of momentum principle

Momentum before collision is equal to momentum after collision

P(before) = P(after)

M1•U1 + M2•U2 = M1•V1 + M2•V2

328 × 19.1 + 790 × 13 = 328 × V1 + 790 × 15.1

16534.8 = 328•V1 + 11929

328•V1 = 16534.8—11929

328•V1 = 4605.8

V1 = 4605.8/328

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3 years ago
If you have 3/4 cup of flour how many eights do you have
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I think it's 6/8, you multiply by 2. 3/4 x 2 = 6/8.
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4 years ago
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