The answer is D i took the test but got it wrong but i got to see the answers
Given :
Mass of person, m = 81 kg.
Area of high heal, A = 3.5 cm² = 0.00035 m².
To Find :
The pressure applied by the heal on the ground.
Solution :
We know, pressure is given by :

Hence, this is the required solution.
Answer:
Average velocity is 0.296 m/s.
Average speed is 4.0 m/s.
Explanation:
Given:
Distance of the circular track is, 
Number of laps ran is, 
Time taken for the run is, 
Now, total distance covered in 5.4 laps = 
Also, since the path is a circle, the final position of the athlete after 5.4 laps will be 0.4 of 400 m ahead of the starting point.
Distance covered in 0.4 laps is, 
Therefore, the displacement of the athlete will be 160 m as the athlete is 160 m ahead of the starting point and displacement depends on the initial and final points only.
Now, average velocity is given as:

Average speed is the ratio of total distance covered to total time taken.
So, average speed = 
Answer:
Explanation:
Given that,
Mass of first car
M1= 328kg
The car is moving in positive direction of x axis with velocity
U1 = 19.1m/s
Velocity of second car
U2 = 13m/s, in the same direction as the first car..
Mass of second car
M2 = 790kg
Velocity of second car after collision
V2 = 15.1 m/s
Velocity of first car after collision
V1 =?
This is an elastic collision,
And using the conservation of momentum principle
Momentum before collision is equal to momentum after collision
P(before) = P(after)
M1•U1 + M2•U2 = M1•V1 + M2•V2
328 × 19.1 + 790 × 13 = 328 × V1 + 790 × 15.1
16534.8 = 328•V1 + 11929
328•V1 = 16534.8—11929
328•V1 = 4605.8
V1 = 4605.8/328
V1 = 14.04 m/s
The velocity of the first car after collision is 14.04 m/s
I think it's 6/8, you multiply by 2. 3/4 x 2 = 6/8.